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mr Goodwill [35]
3 years ago
8

______ is a disadvantage of EDI.

Computers and Technology
1 answer:
Artist 52 [7]3 years ago
6 0

Answer:The number of standards

Explanation:Electronic data interchange (EDI)  is the mechanism through which data is interchanged in the system electronically.It is mostly found in the business field for exchanging of data.

As EDI helps in making message accurate by decreasing the length and also has beneficial features of maintaining the security and increasing productivity ,hence these factor are not considered as the disadvantage .

Too many standard present in the EDI make the working complex by limiting the processing in the small business as compared with large organization.

 

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List three differences between word and excel
34kurt

Answer:

Word: A word processor

           File extension is .doc

          Images, texts, and graphic styles can be added

Exel: A spreadsheet software

       Comprises rows and columns which combine to form cells

       File extension is .xls

I hope i helped! xoxo

4 0
2 years ago
Web-based application software is software that ________.
d1i1m1o1n [39]
Web-based application - this is a special kind of applications that operate in the global Internet via HTTP. The user interacts with the program, usually carried out through the browser.
8 0
3 years ago
Of the people working in concert with security teams to ensure data quality and protection, the head of information management i
Svet_ta [14]

Answer:

true

Explanation:

because Internet

because Internet

3 0
2 years ago
Given an integer variable count, write a statement that displays the value of count on the screen. Do not display anything else
Irina-Kira [14]

Answer:

cout<<count;

Explanation:

The above statement is in c++ which display the value of count .The cout statement is used in c++ to print the value on console .

Following are the code in c++

#include <iostream> // header file

using namespace std; // namespace

int main() // main method

{

   int count=90; // count variable

   cout<<count; // display the value of count

   return 0;

}

Output:

90

In this program we have declared a count variable of integer type which is initialized by 90 and finally displays the value of count on the screen.

4 0
3 years ago
Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
5 0
3 years ago
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