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blondinia [14]
3 years ago
12

Help ASAP

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

p=\frac{181}{301}

Step-by-step explanation:

30100 have dogs, 18100 have cats.

The question simply asks for a union scenario thus the law of AND & OR is applicable.

Therefore:-Those who have both cats and dogs partially have cats.

P(X=both \ cat \ and \ dog)=\frac{18100}{30100}\\p=\frac{181}{301}

Shkiper50 [21]3 years ago
3 0

Answer:

3/5

Step-by-step explanation:

The correct answer is 3/5 i just did the workbook

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marysya [2.9K]

Answer:

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Step-by-step explanation:

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8 0
4 years ago
Find the area of a trapezoid h= 4 b1= 1 1/2 b2 = 3 1/2
nlexa [21]

Answer:

10

Step-by-step explanation:

if

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6 0
3 years ago
Express this number in standard form<br> 5.301 x 107 = ?
defon

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Thirteen equal minus two (y minus four ) plus three y
Sav [38]

Answer:

5

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Find the maximum revenue for the revenue function r(x) = 382 x − 0.6x 2. (round your answer to the nearest cent.)
Gwar [14]
The coefficient of x² is is a negative 0.6, so this function has a maximum value.
the max value of a quadratic function is the value of f(x) when x=-b/2a, 
in this case, a=-0.6, b=382
so x=382/1.2=
r(382/1.2)=-0.6(382/1.2)²+382*(382/1.2)
use a calculator: 60801.67 is the number I got. 
3 0
3 years ago
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