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3 years ago

In rhombus ABCD, AB = 13 and AC = 25. Find the area of the rhombus to the nearest tenth.

1 answer:

8 0

$the\ area\ of\ the\ rhombus=\\=half\ the\ product\ of\ the\ diagonals\ of\ a\ rhombus\\\\A= \frac{1}{2}\cdot |AB|\cdot |AC|=\frac{1}{2}\cdot 13\cdot 25= 162.5\ [u^2]$

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What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?

11111nata11111 [884]

Answer:

$R' = (-1,-0.5)$

Step-by-step explanation:

See attachment for complete question.

From the attachment:

$P = (-3,-3)$

$R = (1,2)$

Dilation:

$D_{(0.5,P)}$

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

$R = (1-(-3),2-(-3))$

$R = (1+3,2+3)$

$R = (4,5)$

Next, apply dilation factor 0.5

$R' = R * 0.5$

$R' = (4,5) * 0.5$

$R' = (4* 0.5,5* 0.5)$

$R' = (2,2.5)$

Lastly, measure R' from the origin by adding the coordinates of P to R'

$R' = (2+(-3),2.5+(-3))$

$R' = (2-3,2.5-3)$

$R' = (-1,-0.5)$

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2 years ago

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Lelechka [254]

Answer:

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Step-by-step explanation:

Given: 0.95 = log x,

we can conclude that:

0.95 log x

10 = 10

0.95

which in turn is equivalent to x = 10 whose value is 8.91

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3 years ago

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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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