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3 years ago

In rhombus ABCD, AB = 13 and AC = 25. Find the area of the rhombus to the nearest tenth.

1 answer:

8 0

$the\ area\ of\ the\ rhombus=\\=half\ the\ product\ of\ the\ diagonals\ of\ a\ rhombus\\\\A= \frac{1}{2}\cdot |AB|\cdot |AC|=\frac{1}{2}\cdot 13\cdot 25= 162.5\ [u^2]$

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What's <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B8%7D%20" id="TexFormula1" title=" \frac{1}{8} " alt=" \frac{1}{

ohaa [14]

112(1/8)

=(112/1)(1/8)

=(112)(1)/(1)(8)

=112/8

=14

answer is 14.

6 0

2 years ago

W sklepie spożywczym jest 11,73 kg cukierków czekoladowych. Pierwszy klient kupił 48 dag cukierków. Drugi klient kupił 4/5 pozos

Elenna [48]

Answer:

<h2>The last costumers got 2.25 kilograms of chocolate candies.</h2>

Step-by-step explanation:

The question is

<em> There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?</em>

<em />

Givens

The total amount of chocolate candies is 11.73 kilograms.
First costumer bought 48 dag of candies. (1 kg equals 100 dags)
Second costumer bougth 4/5 of the remaining.
Another three costumers bought the same amount of candy.

Let's transform 48 dag to kilograms.

$48dag \times \frac{1kg}{100dag}= 0.48 \ kg$

Therefore, the first costumer bought 0.48 kilograms of candies.

The remaining amount is: $11.73kg-0.48kg=11.25kg$

Now, we need to multiply the remaining amount of candies with 4/5

$\frac{4}{5} \times 11.25kg=9 \ kg$

Therefore, the second costumer bought 9 kilograms of chocolate candies.

At last, we need to find the new remaining part of candies, which is

$11.25-9=2.25 \ kg$

Therefore, the last costumers got 2.25 kilograms of chocolate candies.

4 0

3 years ago

Currently, Nora is 3 time as old as damon. In 8 years she will be only 2 time as old as Damon. How old will Damon will be in 8 y

Ann [662]

In 8 years Damon will be 16 year's old.

We have Nora who 3 time as old as Damon and in 8 years she will be only 2 time as old as Damon.

We have to determine how old will Damon be in 8 years.

<h3>If your present age is x and your sister is 4 years elder than you. Than what will be her age after 5 years from now.</h3>

Your present age = x.

Hence, your sister's present age = x + 4.

After five years, your age = x + 5.

Hence, your sister's age will be = x + 9.

According to question, we have -

Assume that the present age of Damon is x.

Then, Nora's age will be = y = 3x.

After 8 years -

Damon's age = x + 8

Nora's age = 3x + 8

Therefore -

3x + 8 = 2(x + 8)

3x + 8 = 2x + 16

x = 8

Hence, in 8 years Damon will be = 8 + 8 = 16 year's old.

To solve more questions on Age determination, visit the link below -

brainly.com/question/14580151

#SPJ1

6 0

1 year ago

Find the measure of the indicated angle below

Norma-Jean [14]

Answer:

The measure of x is $70\°$

Step-by-step explanation:

we know that

The formula to calculate the sum of the internal angles of a polygon is equal to

$S=(n-2)*180\°$

where

n is the number of sides

In this problem we have

$n=9\ sides$

substitute

$S=(9-2)*180\°=1,260\°$

Find the measure of each internal angle

Divide the sum of the internal angles by the number of sides

$1,260\°/9=140\°$

The value of x is half the measure of internal angle

$x=140\°/2=70\°$

8 0

3 years ago

Exercise which car can travel farther on 1 gallon of gas?

Julli [10]

Answer:

nidE sme olome tib ary dae usa arajkpnoder xd jsaludos aja lpa

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers