In rhombus ABCD, AB = 13 and AC = 25. Find the area of the rhombus to the nearest tenth.

1 answer:

8 0

$the\ area\ of\ the\ rhombus=\\=half\ the\ product\ of\ the\ diagonals\ of\ a\ rhombus\\\\A= \frac{1}{2}\cdot |AB|\cdot |AC|=\frac{1}{2}\cdot 13\cdot 25= 162.5\ [u^2]$

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