What is a solution to the following system of equations?<br><br> x2 + y2 = 13 <br> 2x

Order the set of numbers from least to greatest.<br><br><br> {2.5, 4, 23, 1, 5, 3, 0.66}

joja [24]

0.66, 1, 2.5, 3, 4, 5, 23

7 0

3 years ago

What affects the size of an angle? A. The length of its sides B. The direction of one side C. Its orientation in space D. The am

MrMuchimi

Answer:

<h3>D. The amount of rotation of one side.</h3>

Step-by-step explanation:

We need to explain the statement " What affects the size of an angle? ".

Given options are

A. The length of its sides

B. The direction of one side

C. Its orientation in space

D. The amount of rotation of one side.

The correct option would be :

<h3>D. The amount of rotation of one side.</h3>

<em>Because as the one side rotated, it makes a greater or smaller arc between the two lines. That would affects the size of an angle. </em>

4 0

3 years ago

Read 2 more answers

Express 0.52 as a fraction

ioda

52/100
26/50
13/25
These will all do.

7 0

3 years ago

Read 2 more answers

For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

(c) Margin of error ( E) = $500

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

7 0

4 years ago

What is the area of this isosceles triangle.

frez [133]

Answer:

A=672 m²

Step-by-step explanation:

a²+b²=c² (to find h)

14²+b²=50²

196+b²=2,500

b²=2,304

√b²=√2,304

b=48

h=48

(base×height)÷2

(28×48)÷2

1,344÷2

A=672 m²

6 0

3 years ago

What is a solution to the following system of equations? x2 + y2 = 13 2x - y = 4