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Katyanochek1 [597]
3 years ago
12

Find BC. Round to the nearest tenth

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0
<span>Using LAW OF SINES Round to the nearest tenth. 
Find BC: triangle is laying on it's side with the point to the right point(A).

B to C= 61 degrees
C to A= 23 cm
A to B= 12 degrees
--------------------
If I interpret this correctly:
Angle A = 61º

Angle C = 12º
--> B = 103º
-------------
Side b = 23 cm
--------------
BC is side a, opposite angle A
--------------
23/sin(103) = a/sin(61)
a = 23*sin(61)/sin(103)
a =~ 20.6 cm 

Hope this helped :)</span>
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Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

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Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
What's the distance between (0,2) and (0,8)?
N76 [4]

Answer:

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Step-by-step explanation:

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\boxed{\textcolor{steelblue}{\text{Distance between 2 points}= \sqrt{(y_1 - y_2)^{2} + (x_1 - x_2)^{2}  } }}

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2 years ago
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The resulting composite function (f∘f)(x) is x⁴+2x²+2

When a function is written inside another function, it is known as a composite function

Given the function f(x)=x²+1,

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This means we will need to replace x with x²+1 in f(x) as shown:

f(x²+1) = (x²+1)²+1

Expand

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Hence the resulting composite function (f∘f)(x) is x⁴+2x²+2

Learn more here: brainly.com/question/3256461

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