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torisob [31]
4 years ago
6

Giving brainliest answer man What is 2737388/0 * 10^8

Mathematics
1 answer:
tangare [24]4 years ago
8 0

The correct answer is that you can not divide by 0. so the result is undefined

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Kirstin knows that the initial fee for adopting a dog from the animal shelter is $75. This fee needs to be considered when calcu
irina [24]

Answer:

The function is represented by C(d) = 75\,USD + r\cdot d.

Step-by-step explanation:

In this case, we must observe that total cost of the dog (C(d)) is the sum of two components: i) <em>Fixed cost</em> (C_{f}) - Adoption fee, ii) <em>Variable cost</em> (C_{v}) - Daily cost of feeding the dog, both measured in US dollars.

In addition, we suppose that variable cost is directly proportional to the number of days that Kirstin owns her dog. That is:

C (d) = C_{f} + C_{v}

C(d) = C_{f} + r\cdot d

Where:

d - Number of days that Kirstin owns her dog, measured in days.

r - Daily feeding costs, measured in US dollars per day.

If C_{f} = 75\,USD, then:

C(d) = 75\,USD + r\cdot d

The function is represented by C(d) = 75\,USD + r\cdot d.

8 0
3 years ago
Input and output of 2x+6
Reil [10]
You need to write the entire function:  y = f(x) = 2x + 6.
Here the input quantity is x, and the output is y (or f(x)).
8 0
3 years ago
Angela starts a blog about wheelchair basketball. In the first 4 days,
kykrilka [37]
165 new subs.

22 divided by 4 is 5.5. So approximately 5.5 new subs per day. Multiply that by 30 is 165
8 0
3 years ago
1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves
erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx

\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx

\ln|y| = x - \ln|x+1| + C

When x = 0, we have y = 2, so we solve for the constant C :

\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)

Then the particular solution to the DE is

\ln|y| = x - \ln|x+1| + \ln(2)

We can go on to solve explicitly for y in terms of x :

e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}

(b) The curves y = x² and y = 2x - x² intersect for

x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1

and the bounded region is the set

\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}

The area of this region is

\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}

7 0
3 years ago
Using the data from the theoretical probability table, what is the probability of the spinner landing only once on yellow in two
pogonyaev

Answer:

0.375 on edge

Step-by-step explanation:

6 0
3 years ago
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