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2 years ago

8

One number is 2 more than another. the difference between their squares is 60 what are the numbers

1 answer:

weeeeeb [17]2 years ago

3 0

Expand (x+2)^2: x^2 + 4x + 4 : remember that (a+b)^2 = a^2 + 2ab + b^2
So: x^2 + 4x + 4 - x^2 = 60

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The standard deviation of a sample taken from population A is 17.6 for a sample of 25.

lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation $\sigma_A$ is

$\sigma_A = 17.6$

The sample size $n_A$ is:

$n_A = 25$ .

For the sample of population B, the standard deviation $\sigma_B$ is

$\sigma_B = 21.2$

The sample size $n_B$ is:

$n_B = 30$ .

Then the standard deviation for the difference of means has the following form:

$\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}$

Finally

$\sigma=\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}}\\\\\sigma= 5.23$

7 0

3 years ago

Allushta [10]

Thanks for the helpful answers

5 0

2 years ago

Read 2 more answers

Terday. Priya successfully made 6 free throws. Today, she made 75% as

tatuchka [14]

Answer:

10

Step-by-step explanation:

Yesterday, Priya successfully made 6 free throws.

Today, she made 75% as many as yesterday.

We are asked to calculate the number of successful free throws that Priya made today.

So, the number will be $6 (1 + \frac{75}{100} ) = 10.5$ .

Since it is the number of successful free throws, so it will be 10 throws. ( Answer )

4 0

3 years ago

a storeroom 21 feet long, 15 feet wide, and 11 feet high was enlarged to a length of 25 feet and a width of 17 feet. how many cu

xenn [34]

<h2>1210 cubic feet</h2>

Step-by-step explanation:

Initial dimensions of the storeroom were $21\text{ }ft$ length, $15\text{ }ft$ width and $11\text{ }ft$ height.

The room is in the shape of a cuboid. Volume of a cuboid = $V=l\times b\times h$ , where $l,b,h$ are the length, width and height of the cuboid.

So, Volume of storeroom initially = $21\text{ }ft\text{ }\times15\text{ }ft\text{ }\times11\text{ }ft\text{ }=3465\text{ }ft^{3}\text{ }$

Finally, the length was increased to $25\text{ }ft$ and width to $17\text{ }ft$ .

Final volume of storeroom = $25\text{ }ft\text{ }\times 17\text{ }ft\text{ }\times 11\text{ }ft\text{ }=4675\text{ }ft^{3}\text{ }$

Increase in volume = $4675\text{ ft}^{3}-3465\text{ ft}^{3}=1210\text{ ft}^{3}$

∴ 1210 cubic feet of storage was added.

7 0

3 years ago

How do i do the problem

cluponka [151]

The correct answer is 4 and 1/8

6 0

3 years ago