Answer:
P(X = 17) = 0.3002
Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:

We want P(X = 17). So


P(X = 17) = 0.3002
Assuming number cube has 6 sides
probablity is (desiredoutcomes)/(total possible ouctomes)
since it is 450 times
total possible outcomes=450
experimiental probablity is the one actaully obtained by doing it
theoretical is the predicted amount
so theoretical probablity of rolling a 3 is 1 number out of 6 or 1/6 or 75 times out o 450 times
experimiental is the actaull one so67 out of 450 or 67/450
theoretical is 1/6 or 75/450
experimental is 67/450
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
Answer:
that problem is imposable
Step-by-step explanation: