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Talja [164]
3 years ago
13

$r(x)$ has domain $\{-1,0,1,2\}$ and range $\{0,2,4,6\}$. $s(x)$ has domain $\{1,2,3,4\}$ and is defined by $s(x)=x+1$. What is

the sum of all possible values of $s(r(x))$?
Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

8290

Step-by-step explanation:


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GalinKa [24]

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iVinArrow [24]

Answer:

1. x = +/- 2\sqrt{2} - 7

2. x = 3 +/- 2i\sqrt{3}

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Step-by-step explanation:

1. Divide both sides by 2: (x + 7)^2 = 8

Square root both sides: x + 7 = +/- 2\sqrt{2}

Subtract 7 from both sides: x = +/- 2\sqrt{2} - 7

2. Square root both sides: x - 3 = \sqrt{-12}

Since there is a negative inside the radical, we need to have an imaginary number: i=\sqrt{-1} . So, \sqrt{-12} =i\sqrt{12} =2i\sqrt{3}

Add 3 to both sides: x = 3 +/- 2i\sqrt{3}

3. Divide by -5 from both sides: (n - 2)^2 = -2

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Again, we have to use i: n-2=\sqrt{-2} =i\sqrt{2}

Add 2 to both sides: n = 2 +/- i\sqrt{2}

Hope this helps!

8 0
3 years ago
Read 2 more answers
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