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wolverine [178]
3 years ago
10

A painting measures 2.4 feet from left to right. It's hung in the center of a rectangular wall measuring 20 feet from left to ri

ght. What is the distance between the right edge of the painting and the right edge of the wall? Assume the painting does not tilt
Mathematics
2 answers:
otez555 [7]3 years ago
5 0
2.1 feet. If you take the middle of the wall it would be 10 feet. Take the 4.2 which equals 4.2,feet on each side.1/2 of the picture is 2.1.
kvv77 [185]3 years ago
4 0
If the painting lies in the middle of the rectangle and half of 20 f is 10  so then half of the painting that is on half of the wall would be only 1.2f if you take 10-1.2= 8.8f your final answer.
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Which system of equations below will have infinite solutions?
ipn [44]

Answer:

All

Step-by-step explanation:

Because there are no equations for them so for all we know they all could have infinite solutions.

5 0
2 years ago
10 points please help ASP i need to do a lot of work and I'm behind
tino4ka555 [31]

Answer: 1. Yellow, green, black, white, blue, red. yes equally likely

2. heads, tails. yes equally likely

3. possibilites: yellow heads, yellow tails, green heads, green tails, black heads, black tails, white heads, white tails, blue heads, blue tails, red heads, red tails.

4. 1/12

5. still 1/12

Step-by-step explanation:

3 0
3 years ago
X+y=4<br> X-3y=12<br> Graph?
AlekseyPX
I'll solve it algebraically


x+y=4
x-3y=12

multiply first equatoin by -1 and add to second

-x-y=-4
<u>x-3y=12 +</u>
0x-4y=8


-4y=8
divide both sides by -4
y=-2

sub back

x+y=4
x+-2=4
add 2 to both sides
x=6

x=6
y=-2
(6,-2)
8 0
3 years ago
Help me please I donr understand this ​
Serggg [28]
For the function w,w(9)

8 0
3 years ago
Read 2 more answers
4. Suppose that you have an enormous grapefruit that is 92% water (by weight). The grapefruit weights 100 pounds. If the water c
Anton [14]

Answer:

80 pounds.

Step-by-step explanation:

Let W₁ be the initial weight of water in the grapefruit, W₂ be the weight of water in the grapefruit after evaporation, and M be the total weight of the grapefruit after evaporation. Assuming that, originally, the grapefruit weighed 100 pounds with a 92% water content and the weight of the "non-water" part of the fruit (100 - W₁) does not change. The final weight of the grapefruit (M) is given by:

W_1=0.92*100=92\\W_2=0.90*M\\W_2+(100-W_1) = M\\W_2=M-8\\(1-0.9)M=8\\M=80

The grapefruit now weighs 80 pounds.

8 0
3 years ago
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