we represent the first integer with x and the second even integer equal to x + 2. Using the given statement, we translate it into equation: x + x + 2 = 244. we add like terms, y and y equal then to 2x + 2 = 244. y is equal to 121 while the other integer has to be equal to 123. The answer is 121.
Answer:
probability that actual service time will be less than or equal to five minutes = P(X <= 5) = 1 - e-15(5/60) = 0.714 or 71.4%
Step-by-step explanation:
The identification of the average arrival rate of customers(v) and the average service rate(u) must be done in order to solve this kind of problem .
In this case, on average, 12 customers arrive each hour. On average, the service rate is 15 customers per hour.
The arrival rate follows the exponential distribution.
probability that actual service time will be less than or equal to 't' minutes P(X <= t) = 1 - e-u(t/60)
probability that actual service time will be less than or equal to five minutes = P(X <= 5) = 1 - e-15(5/60) = 0.714 or 71.4%
Answer:
Probability that first sock is blue is 0.33 and Probability that second sock is red is 0.16
Step-by-step explanation:
Number of red socks = 2
Number of white socks = 6
Number of blue socks = 4
Total socks in drawer = 2+6+4 = 12
The formula used to calculate probability is: ![Probability=\frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes}](https://tex.z-dn.net/?f=Probability%3D%5Cfrac%7BNumber%20%5C%20of%20%5C%20favourable%20%5C%20outcomes%7D%7BTotal%20%5C%20number%20%5C%20of%20%20%5C%20outcomes%7D)
We are given you draw out a sock, return it, and draw out a second sock.
We need to find the probability that the first sock is blue and the second sock is red?
Using formula:
Probability that first sock is blue = 4/12 = 1/3 = 0.33
Probability that second sock is red = 2/12 = 1/6 = 0.16
So, Probability that first sock is blue is 0.33 and Probability that second sock is red is 0.16
x=[-6] and x=[10] if you are NOT a boy came and see me
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