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lapo4ka [179]
3 years ago
6

For spirit week at a local high school, students were encouraged to wear their school colors of green and white. 1,200 students

wore their school colors while 300 students did not wear green and white. What percent of the school population wore their school colors?
Mathematics
2 answers:
Sergeu [11.5K]3 years ago
4 0

Answer:

80%

Step-by-step explanation:

We are told that 1,200 students wore their school colors of green and white.

Also, we are told that 300 students did not wear school colours green and white.

Thus, total number of students = 1200 + 300 = 1500

Thus;

percent of the school population who wore their school colors is; (1200/1500) × 100% = 80%

Scilla [17]3 years ago
4 0

Answer:

the answer is 16.7

Step-by-step explanation: /=devision sign

1,500 did

  300 didn't

1,800 total

<u>300   = 16.7%           </u>

1,800    100 %                      1,800/300=.167x100=16.7

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MrMuchimi

Answer:

Alright! BTW, the answer to the question is D :)

Step-by-step explanation:

Reflecting across the x-axis, the x-coordinate ALWAYS remains the same, but the y-coordinate is transformed into its opposite. If you forget this, fold along the x line, and you should be able to figure it out. Reflecting across the y-axis, the y-coordinate ALWAYS remains the same, but the x-coordinate is transformed into its opposite. If you forget this, fold along the y line, and you should be able to figure it out.

Hope I helped!

6 0
2 years ago
Y + 2 = -3/4(x+1)<br> Standard form.
evablogger [386]

I have the answer in this picture. But im not sure if this might be really what your asking for.

7 0
3 years ago
In an effort to determine whether any correlation exists between the price of stocks of airlines, an analyst sampled six days of
vovikov84 [41]

Answer:

Check the explanation

Step-by-step explanation:

Following table shows the calculations:

Delta, X      Southwest , Y            X^2              Y^2                      XY

45.96               38.76               2112.3216     1502.3376          1781.4096

46.8                 45.41                2190.24         2062.0681        2125.188

47.93                15.7                 2297.2849      246.49            752.501

51.78                49.58              2681.1684      2458.1764        2567.2524

52.17                44.34              2721.7089      1966.0356        2313.2178

47.36                18                   2242.9696            324               852.48

Total 292       211.79               14245.6934      8559.1077      10392.0488

Sample size: n =6

Now

S_{yy}=\sum y^{2}-\frac{\left (\sum y \right )^{2}}{n}=1083.27

S_{xx}=\sum x^{2}-\frac{\left (\sum x \right )^{2}}{n}=35.03

S_{xy}=\sum xy-\frac{\left (\sum x \right )\left (\sum y \right )}{n}=84.94

The coefficient of correlation is :

r=\frac{S_{xy}}{\sqrt{S_{xx}S_{yy}}}=0.436

7 0
3 years ago
WILL MARK BRAINLIEST
dsp73
<h3>Refer to the diagram below</h3>
  1. Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
  2. Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
  3. Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
  4. Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
  5. Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.

Refer to the diagram below for examples of what I mean.

5 0
3 years ago
Please use system of linear equations by elimination OR substitution. I need the work as well please.
Olin [163]

1) P= 64 cm, width = x, length = 14 + x

64 = x + x + 14 + x + 14 + x

64 = 4x + 28

4x = 64 - 28

4x = 36

x = 36/ 4

x = 9

AREA = 9 x (9+14)

Area = 9 x 23

Area = 207 cm

2) smaller no. = y, bigger no. = x

x - y = 3

2x+1/2y=36

Next, multiply 2 to first equation and find y:

2x-2y=6

5/2y=30

y = 12

Substitue y to x-y=3 to find x,

x = 15

3) x = pencil, y = pen

5x + 4y = $6.15

8x + 3y = 9.85$

8x + 7y = ?

5x + 4y = 6.15$ multiply both sides by -3

8x + 3y = 9.85$ multiply both sides by 4

-15x + 32x = (-3)*6.15 + 4*9.85

7x = 19.87 multiply both sides by 8/7

8x = (8/7) x 19.87

Add both equations:

32y - 15y = 8x6.15 - 5*9.58

17y = 1.3

y = 91/17) x 1.3

7y = (7/17)x 1.3

8x + 7y = (8/7) x 19.87 + (7/17) x 1.3

8x + 7y = $23.244

4) 2l + 2w = 0

2 x 2l + 2 x 1/2w = 40 + 16

l+w = 20

4l+w = 56

I’ve got l = 12 and w = 8

5) answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° = \frac{ab}{bc}

but bc = 20 feet.

⇒ tan 55 ° =   \frac{ab}{20}

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

6) The answer is teh attachment !

7) 3x-x+2=4

HOPE THE ANSWERS HELP!! PL MARK ME BRAINLIEST!

3 0
2 years ago
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