Question

Given a cone 10 feet tall with a diameter of 10 feet, determine the radius of the smaller cone created when a horizontal plane passes through the cone at exactly 4 feet from the base.

Answer 1

Answer:

r=3 ft

Step-by-step explanation:

it is similarity of two triangles

one

perpendicular side=10 ft

base=10/2=5 ft

second

perpendicular side=10-4=6 ft

Base r=?

$\frac{r}{5}=\frac{6}{10}\\r= \frac{6}{10} \times 5=3~ft$