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3 years ago

The nucleus is full of

Physics

2 answers:

Gala2k [10]3 years ago

7 0

<span>include growth,intermediary metabolism,protein,synthesis, and reproduction</span>

Zielflug [23.3K]3 years ago

3 0

The nucleus is full of protoplasm, it is enclosed in a double membrane, and most likely found in eukaryotic cells. It consists of neutrons and protons. And also the nucleus also controls what you do, its basically the "brain of cells." It can control you, whether you're using the bathroom or reproducing, it also directs your metabolism. Hope this helped. (I know I used the word "it" to much.)

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Transforma la siguiente unidad al sistema internacional:<br> 37 ft3

tigry1 [53]

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3 0

3 years ago

An archer pulls a bow string 0.5 m. If the spring constant is 16,000 N/m, what is the energy stored in the bow string?

mars1129 [50]

2000J

Explanation:

Given parameters:

Extension = 0.5m

Spring constant = 16000N/m

Unknown:

Energy stored in the bow string = ?

Solution:

The energy stored in a bow string is an elastic potential energy.

It can be calculated using the expression below;

Elastic energy = $\frac{1}{2}$ K e²

Where k is the spring constant

e is the extension

Input the parameters;

Elastic energy = $\frac{1}{2}$ K e²

= $\frac{1}{2}$ x 16000 x 0.5²

= 2000J

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

3 0

3 years ago

A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated

Lelu [443]

Incomplete question as we have not told to find what quantity.The complete question is here

A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated by vacuum and the inner radius of the outer shell is 5.00 cm.calculate: (a) the capacitance; (b) the radius of the inner sphere; (c) the electric field just outside the surface of the inner sphere.

Answer:

(a) $C=16.7pF$

(b) $r_{a} =3.749cm$

Explanation:

Given data

$Q=3.50nC\\V=210V\\r_{b}=5.0cm$

For part (a)

The Capacitance given by:

$C=\frac{Q}{V}\\ C=\frac{3.50*10^{-9} C}{210V}\\C=1.6666*10^{-11}F\\or\\C=16.7pF$

For part (b)

The Capacitance of coordinates is given as

$C=\frac{4\pi e}{\frac{1}{r_{a} }-\frac{1}{r_{b} } }\\ So\\{\frac{1}{r_{a} }-\frac{1}{r_{b} } }=\frac{4\pi *8.85*10^{-12} }{1.666*10^{-11}}=6.672m^{-1} \\ \frac{1}{r_{a} }=6.672+(1 /0.05)\\\frac{1}{r_{a} }=26.672\\r_{a} =1/26.672\\r_{a} =0.0375m\\r_{a} =3.749cm$

For part (c)

The electric field according to Gauss Law is given by:

$EA=\frac{Q}{e}\\ E=\frac{Q}{4\pi er_{a}^{2} }=\frac{kQ}{r_{a}^{2}}\\ E=\frac{9*10^{9}*3.50*10^{-9} }{(0.0375m)^{2} }\\ E=2.24*10^{4} N/C$

7 0

3 years ago

Your friend claims that weather predictions are just guesses. What would you say to change your friend's mind?

VashaNatasha [74]

To change my friends mind, after they've already said weather predictions are just guesses, I would say they are correct, but not only to they use guesses to predict what will happen, but they also, before hand, use atmospheric tools. They then predict from the data collected. They do both.

4 0

3 years ago

Hello i need help with this!!

mr Goodwill [35]

Answer:

Yes

Explanation:

If lamp A burnt out there would still be a wire above it that connects lamp B and C to the power source

3 0

2 years ago