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3 years ago

By what factor must you increase the intensity of a sound in order to hear a 1.0-dB rise in the sound level?

Physics

1 answer:

bezimeni [28]3 years ago

8 0

Answer:

The right approach will be "1.3". A further explanation is given below.

Explanation:

As we know,

In Decibels, the change in sound volume will be:

= $10log\frac{I_1}{I_2}$

Now,

According to the question,

⇒ $1=10 log \frac{I_1}{I_2}$

By applying cross multiplication and putting the value of log, we get

⇒ $10^{\frac{1}{10} }=\frac{I_1}{I_2}$

⇒ $1.26=\frac{I_1}{I_2}$

⇒ $\frac{I_1}{I_2}=1.3$

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A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result

Virty [35]

Hello!

A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result? A) law of differential mass B) law of conservation of momentum C) law of unequal forces D) law of accelerated collision

We have the following data¹:

ΔP (momentum before impact) = ?

mA (mass) = 10 kg

vA (velocity) = 5 m/s

mB (mass) = 5 kg

vB (velocity) = 0 m/s

Solving:

ΔP = mA*vA + mB*vB

ΔP = 10 kg*5 m/s + 5 kg*0 m/s

ΔP = 50 kg*m/s + 0 kg*m/s

Δp = 50 kg*m/s ← (momentum before impact)

We have the following data²:

ΔP (momentum after impact) = ?

mA (mass) = 10 kg

vA (velocity) = 0 m/s

mB (mass) = 5 kg

vB (velocity) = 10 m/s

Solving:

Δp = mA*vA + mB*vB

Δp = 10 kg*0 m/s + 5 kg*10 m/s

Δp = 0 kg*m/s + 50 kg*m/s

Δp = 50 kg*m/s ← (momentum after impact)

*** Then, which principle explains the result ?

Law of conservation of momentum, since the total momentum of body A and B before impact is equal to the total momentum of body A and B after impact.

Note: Bodies of different masses and velocities may have the same kinetic energy, if proportionality between the units is maintained it can occur that they have the same kinetic energy.

Answer:

B) law of conservation of momentum

_______________________

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5 0

3 years ago

NEED HELP ASAP ONLY ANSWER IF YK THE ANSWERS

nalin [4]

Answer:

there yah go that's the answer

6 0

3 years ago

PROVE THAT G = GM/R² WHERE THE SYMBOLS HAS THEIR USUAL MEANINGS

butalik [34]

Answer:

g=GM/R^2

Universal Gravutation Constant:

f=GM×m/R^2

Force can be also expressed as

f=m×g

so,

mg=GMxm/R^2

The m gets cancelled so

g=GM/R^2

8 0

4 years ago

Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the

yaroslaw [1]

Answer:

K_a = 8,111 J

Explanation:

This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved

initial instant. Just before dropping the particles

p₀ = 0

final moment

p_f = m_a v_a + m_b v_b

p₀ = p_f

0 = m_a v_a + m_b v_b

tells us that

m_a = 8 m_b

0 = 8 m_b v_a + m_b v_b

v_b = - 8 v_a (1)

indicate that the transfer is complete, therefore the kinematic energy is conserved

starting point

Em₀ = K₀ = 73 J

final point. After separating the body

Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²

K₀ = K_f

73 = ½ m_a (v_a² + v_b² / 8)

we substitute equation 1

73 = ½ m_a (v_a² + 8² v_a² / 8)

73 = ½ m_a (9 v_a²)

73/9 = ½ m_a (v_a²) = K_a

K_a = 8,111 J

3 0

3 years ago

if i roll pieces of allium foil in a ball what property of aluminium foil changes as a result of my action

MArishka [77]

Answer:

Malleability

Explanation:

The ability to roll aluminum foil in a ball is the property of metal called malleability.

Metallic bonds in metals makes it possible for them to take different shape without losing internal cohesion.
Metals are malleable and they posses a wide range of physical properties.
A malleable metal can be beaten into sheets and molded into many shapes.

6 0

3 years ago