I believe it’s D but I’m not really sure hope this help a little
Answer:

Step-by-step explanation:


Answer: Lower left corner 
We have 29 people who chose fishing out of 18+29 people who filled out the survey. We don't use 60 because not everyone filled out the survey, and we're only focusing on survey participants. The "times 100" at the end will move the decimal point 2 spots to the right, and convert it to percent form.
For example, if you had 2 people who liked fishing out of 8 total then 2/8 = 0.25 = 25% of the people like fishing.
Answer:
one to one function
Step-by-step explanation:
f(x)=6x+1 can only be a one to one function when x1=x2
Now,
f(x1)=f(x2)
or, 6x1 + 1 = 6x2 + 1
or, 6x1 = 6x2
or, x1 = x2
So f(x)= 6x + 1 is a one to one function