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BigorU [14]
3 years ago
8

I’m need help on these questions can any one answer them

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
6 0

Answer:

5. WAX and XAZ

6. WAZ and ZAX

7. WAX and YAU

8.  ZAY and YAU

Step-by-step explanation:

Complementary Angles always equal 90 degrees

Supplementary Angles always equal 180 degrees

Vertical angles are always congruent

Adjacent angles are always next to each other.

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The nfl regulation extra point is kicked 15 yards from the goal line. How many inches away from the goal line is the extra point
enot [183]

Step-by-step explanation:

That's why, in 2015, the NFL decided to make extra points more difficult, moving them 13 yards back. Since then, the success rate has hovered between 93 percent and 95 percent. Until Sunday, when that ugly day for kickers dropped the success rate below 93 percent on the season.

4 0
2 years ago
X + 5y = -2
natita [175]

Answer:

the answer is -1. please thank my answer please and thank you

3 0
4 years ago
20 points!<br> I need help (asap!!)
EastWind [94]

Answer:

<h2>x = 5</h2><h2>OB = 36</h2><h2>BE = 54</h2>

Step-by-step explanation:

We know that the medians of the triangle divides in a ratio of 2:1. Therefore we have the equation:

\dfrac{9x-9}{2x+8}=\dfrac{2}{1}                <em>cross multiply</em>

1(9x-9)=2(2x+8)             <em>use distributive property a(b + c) = ab + ac</em>

9x-9=(2)(2x)+(2)(8)

9x-9=4x+16                 <em>add 9 to both sides</em>

9x=4x+25                <em>subtract 4x from both sides</em>

5x=25             <em>divide both sides by 5</em>

\boxed{x=5}

OB=9x-9\to OB=9(5)-9=45-9=\boxed{36}

OE=OB:2\to OE=36:2=18\to BE=BO+OE\to BE=36+18=54


8 0
3 years ago
The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

3 0
3 years ago
Help thank you but quick due date is soon
hammer [34]

Answer:

If you reflect point x across the y axis, it will end up at (-1/2,0).

Step-by-step explanation:

5 0
3 years ago
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