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AlladinOne [14]
3 years ago
15

Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r

ectangular field with a length if 25 yards and a width of 35 yards. Who ran a longer distance? Show work to prove your answer.
Mathematics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

Will ran the longer distance.

Step-by-step explanation:

In order to calculate this you have to create a triangle with the values that you are given, and the distance ran would be the hypothenuse, remember the formula for hypothnuse:

H=\sqrt[2]{a^2+b^2}

Now we just insert the values into the formula:

H=\sqrt[2]{a^2+b^2}\\H=\sqrt[2]{40^2+40^2}\\H=56,56

H=\sqrt[2]{a^2+b^2}\\H=\sqrt[2]{25^2+35^2}\\H=43,01

AS you can see the hypothenuse in the square is greater than that of the rectangle, so Will who ran the hypothenuse of the square will be the one that ran the longer distance.

Oksi-84 [34.3K]3 years ago
4 0

Answer: The distance across a rectangular field is longer distance.

Step-by-step explanation:

Since we have given that

Dimension of square = 40 yards

So, Dimensions of rectangle are :

Length = 25 yards

Width = 35 yards

So, Perimeter of rectangle would be

2\times (l+b)\\\\=2\times (25+35)\\\\=2\times 60\\\\=120\ yards

Diagonal of square would be

\sqrt{40^2+40^2}\\\\=\sqrt{1600+1600}\\\\=\sqrt{3200}\\\\=56.56\ yards

Hence, the distance across a rectangular field is longer distance.

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3 years ago
Now, you will consider Option 1, setting a maximum shower time of 10 minutes.
matrenka [14]

The maximum shower time is an illustration of mean and median, and the conclusion is to disagree with Blake's claim

<h3>How to interpret the shower time?</h3>

The question is incomplete, as the dataset (and the data elements) are not given.

So, I will answer this question using the following (assumed) dataset:

Shower time (in minutes): 6, 7, 7, 8, 8, 9, 9, 9, 12, 12, 12, 13, 15,

Calculate the mean:

Mean = Sum/Count

So, we have:

Mean = (6+ 7+ 7+ 8+ 8+ 9+ 9+ 9+ 12+ 12+ 12+ 13+ 15)/13

Mean = 9.8

The median is the middle element.

So, we have:

Median = 9

From the question, we have the following assumptions:

  • The shower time of students whose shower times are above 10 minutes, is 10 minutes
  • Other shower time remains unchanged.

So, the dataset becomes: 6, 7, 7, 8, 8, 9, 9, 9, 10, 10, 10, 10, 10

The mean is:

Mean = (6+ 7+ 7+ 8+ 8+ 9+ 9+ 9+ 10+ 10+ 10+ 10+ 10)/13

Mean = 8.7

The median is the middle element.

So, we have:

Median = 9

From the above computation, we have the following table:

               Initial    Final

Mean         9.8        8.7

Median       9         9

Notice that the mean value changed, but it did not go below 8 as claimed by Blake; while the median remains unchanged.

Hence, the conclusion is to disagree with Blake's claim

Read more about mean and median at:

brainly.com/question/14532771

#SPJ1

5 0
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