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AlladinOne [14]
3 years ago
15

Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r

ectangular field with a length if 25 yards and a width of 35 yards. Who ran a longer distance? Show work to prove your answer.
Mathematics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

Will ran the longer distance.

Step-by-step explanation:

In order to calculate this you have to create a triangle with the values that you are given, and the distance ran would be the hypothenuse, remember the formula for hypothnuse:

H=\sqrt[2]{a^2+b^2}

Now we just insert the values into the formula:

H=\sqrt[2]{a^2+b^2}\\H=\sqrt[2]{40^2+40^2}\\H=56,56

H=\sqrt[2]{a^2+b^2}\\H=\sqrt[2]{25^2+35^2}\\H=43,01

AS you can see the hypothenuse in the square is greater than that of the rectangle, so Will who ran the hypothenuse of the square will be the one that ran the longer distance.

Oksi-84 [34.3K]3 years ago
4 0

Answer: The distance across a rectangular field is longer distance.

Step-by-step explanation:

Since we have given that

Dimension of square = 40 yards

So, Dimensions of rectangle are :

Length = 25 yards

Width = 35 yards

So, Perimeter of rectangle would be

2\times (l+b)\\\\=2\times (25+35)\\\\=2\times 60\\\\=120\ yards

Diagonal of square would be

\sqrt{40^2+40^2}\\\\=\sqrt{1600+1600}\\\\=\sqrt{3200}\\\\=56.56\ yards

Hence, the distance across a rectangular field is longer distance.

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