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AlladinOne [14]
3 years ago
15

Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r

ectangular field with a length if 25 yards and a width of 35 yards. Who ran a longer distance? Show work to prove your answer.
Mathematics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

Will ran the longer distance.

Step-by-step explanation:

In order to calculate this you have to create a triangle with the values that you are given, and the distance ran would be the hypothenuse, remember the formula for hypothnuse:

H=\sqrt[2]{a^2+b^2}

Now we just insert the values into the formula:

H=\sqrt[2]{a^2+b^2}\\H=\sqrt[2]{40^2+40^2}\\H=56,56

H=\sqrt[2]{a^2+b^2}\\H=\sqrt[2]{25^2+35^2}\\H=43,01

AS you can see the hypothenuse in the square is greater than that of the rectangle, so Will who ran the hypothenuse of the square will be the one that ran the longer distance.

Oksi-84 [34.3K]3 years ago
4 0

Answer: The distance across a rectangular field is longer distance.

Step-by-step explanation:

Since we have given that

Dimension of square = 40 yards

So, Dimensions of rectangle are :

Length = 25 yards

Width = 35 yards

So, Perimeter of rectangle would be

2\times (l+b)\\\\=2\times (25+35)\\\\=2\times 60\\\\=120\ yards

Diagonal of square would be

\sqrt{40^2+40^2}\\\\=\sqrt{1600+1600}\\\\=\sqrt{3200}\\\\=56.56\ yards

Hence, the distance across a rectangular field is longer distance.

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A right triangle has one angle that measures 25º. What is the measure of the other acute<br> angle?
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Answer:

65

Step-by-step explanation:

All the angles in a right triangle add up to 180

plug in what we know and we get

90+25+x=180

115+x=180

x=65

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Step-by-step explanation:

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3 years ago
Write and solve an inequality for the following sentence: Jan has saved $50 in her saving account and needs to save at least $26
Juliette [100K]

50 + x ≥ 268

X ≥ 218

STEP BY STEP WORK

50 + x ≥268
-50 -50

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8 0
3 years ago
Howard is designing a chair swing ride. The swing ropes are 4 44 meters long, and in full swing they tilt in an angle of 2 3 ∘ 2
qaws [65]

Question:

Howard is designing a chair swing ride. The swing ropes are 4 meters long, and in full swing they tilt in an angle of 23°. Howard wants the chairs to be 3.5 meters above the ground in full swing. How tall should the pole of the swing ride be? Round your final answer to the nearest hundredth.

Answer:

7.18 meters

Step-by-step explanation:

Given:

Length of rope, L = 4 m

Angle = 23°

Height of chair, H= 3.5 m

In this question, we are to asked to find the height of the pole of the swing ride.

Let X represent the height of the pole of the swing ride.

Let's first find the length of pole from the top of the swing ride. Thus, we have:

cos \theta = \frac{h}{L}

Substituting figures, we have:

cos(23) = \frac{h}{4}

Let's make h subject of the formula.

h = 4cos(23) = 3.68

The length of pole from the top of the swing ride is 3.68 meters

To find the height of the pole of the swing ride, we have:

X = h + H

X = 3.68 + 3.5

X = 7.18

Height of the pole of the swing ride is 7.18 meters

3 0
4 years ago
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