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AlladinOne [14]
3 years ago
15

Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r

ectangular field with a length if 25 yards and a width of 35 yards. Who ran a longer distance? Show work to prove your answer.
Mathematics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

Will ran the longer distance.

Step-by-step explanation:

In order to calculate this you have to create a triangle with the values that you are given, and the distance ran would be the hypothenuse, remember the formula for hypothnuse:

H=\sqrt[2]{a^2+b^2}

Now we just insert the values into the formula:

H=\sqrt[2]{a^2+b^2}\\H=\sqrt[2]{40^2+40^2}\\H=56,56

H=\sqrt[2]{a^2+b^2}\\H=\sqrt[2]{25^2+35^2}\\H=43,01

AS you can see the hypothenuse in the square is greater than that of the rectangle, so Will who ran the hypothenuse of the square will be the one that ran the longer distance.

Oksi-84 [34.3K]3 years ago
4 0

Answer: The distance across a rectangular field is longer distance.

Step-by-step explanation:

Since we have given that

Dimension of square = 40 yards

So, Dimensions of rectangle are :

Length = 25 yards

Width = 35 yards

So, Perimeter of rectangle would be

2\times (l+b)\\\\=2\times (25+35)\\\\=2\times 60\\\\=120\ yards

Diagonal of square would be

\sqrt{40^2+40^2}\\\\=\sqrt{1600+1600}\\\\=\sqrt{3200}\\\\=56.56\ yards

Hence, the distance across a rectangular field is longer distance.

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Step-by-step explanation:

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We conclude that the menager use the hypergeometric distribution.

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<em>1: 13,148,719.2 beats</em>

<em>2: 5 5/6 days</em>

<em>3: 7 days, 5 hrs, and 2 minutes</em>

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<em>Hope this helped. Have a good day~</em>

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4 years ago
If it is Saturday, then it is the weekend.
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Answer:

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B) False

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6 0
4 years ago
The numerical value of sin²5° + sin²10° + sin²15° +... sin²85° + sin²90° is equal a) 17/2 b) 19/2 c) 15/2 d) 13/2​
Vikki [24]

Answer: b)~\Large\boxed{\frac{19}{2} }

Step-by-step explanation:

<h3>Given expression</h3>

sin²5° + sin²10° + sin²15° +... sin²85° + sin²90°

<h3>Concept:</h3>

sin²x + cos²x = 1

sin(x) = cos (90 - x)

<u />

<u>There are in total these terms:</u>

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90

<u>In total, there are 18 terms, and the first one matches with the second to the last one:</u>

5 -- 85

10 -- 80

.

.

.

40 -- 50

<u />

<u>There are 2 terms left over:</u>

sin²45 and sin²90

<h3>Convert the first half of the sine terms (sin²5 - sin²40) to the cosine terms</h3>

sin²5 = cos² (90 - 5) = cos²85

sin²10 = cos² (90 - 10) = cos²80

.

.

.

sin²40 = cos² (90 - 40) = cos²50

<h3>Simplify the 16 grouped terms </h3>

<em>i.e. sin²85 and cos²85</em>

Using the concept of sin²x + cos²x = 1

sin²85 + cos²85 = 1

sin²80 + cos²80 = 1

.

.

.

sin²50 + cos²50 = 1

Total = (16/2) × 1 = 8 × 1 = 8

<h3>Evaluate the 2 terms that are left over</h3>

sin²45 = (sin45) (sin45) = (√2 / 2) (√2 / 2) = 1/2

sin²90 = (sin90) (sin 90) = (1) (1) = 1

<h3>Add all the terms together</h3>

8+\dfrac{1}{2} +1=\Large\boxed{\frac{19}{2} }

Hope this helps!! :)

Please let me know if you have any questions

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1 year ago
using figures below, identify the corresponding parts of each of the triangles. then write a similarity statement that includes
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7446785433333478853246743
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