It's for my sister she wants me to do it HELP HER

What is the volume of a square pyramid with a base length of 6cm and a height of 9cm?

emmainna [20.7K]

Answer:
Volume = 108 cm ³

Explanation:
For a square pyramid, the volume can be calculated as follows:
Volume = $\frac{1}{3}$ * area of base * height
Volume = $\frac{1}{3}$ * side² * height
We have:
side length = 6 cm
height = 9 cm
Therefore:
Volume = $\frac{1}{3}$ * 36 * 9 = 108 cm ³

Hope this helps :)

8 0

4 years ago

Identify the interval on which the quadratic function is positive.

Alenkasestr [34]

Answer:

$\textsf{1. \quad Solution: $1 < x < 4$,\quad Interval notation: $(1, 4)$}$

$\textsf{2. \quad Solution: $-2 < x < 4$,\quad Interval notation: $(-2, 4)$}$

Step-by-step explanation:

<h3>Question 1</h3>

The intervals on which a quadratic function is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a negative leading coefficient, the parabola opens downwards. Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x-1=0 \implies x=1$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is positive is:

Solution: 1 < x < 4
Interval notation: (1, 4)

<h3>Question 2</h3>

The intervals on which a quadratic function is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a positive leading coefficient, the parabola opens upwards. Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x+2=0 \implies x=-2$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is negative is:

Solution: -2 < x < 4
Interval notation: (-2, 4)

3 0

1 year ago

I’ll give u brainliest!! what is the area of shape 1, 2 and 3

nevsk [136]

Answer:

Shape 1: 25.915

Shape 2: 102.85

Shape 3: 142

Step-by-step explanation:

For shape 1, you have to divide 7.1 to get half the width of the triangle. You get 3.55 from that, and then finding the triangle itself you have to do 7.3*3.55 to get 25.915. For shape 2, you first do the harder parts (the triangles) and since there is two of them we don't need to half the width of each triangle. But first to get the width, we need to do 20-17.4=2.6. But since there are 2 triangles we need to divide that by 2 to get 1.3. Then you multiply that by 5.5 to get the final area of both triangles which is 7.15. Next you simply find the rectangle which is 17.4*5.5=95.7. You add the triangles area to get 102.85. Finally for shape 3 you simply do 7.1*20=142.

3 0

3 years ago

Read 2 more answers

Use the Pythagorean Theorem to find the missing side. C=8, a=4, find b. Simplify your answer. Use a radical expression in lowest

DanielleElmas [232]

4^2+b^2=8^2
16+b^2=64
-16. -16
b^2= 48
Sq root each side
b= sq rt 16 sq rt 3
b= 4 sq rt 3

7 0

3 years ago

Read 2 more answers

The triangle shown below has an area of 22 units. Find the missing side.

emmasim [6.3K]

Answer: