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AleksandrR [38]
3 years ago
12

Trisha drew the figure below what figure did she draw

Mathematics
1 answer:
galben [10]3 years ago
8 0
She drew whatever she drew
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A motorboat can maintain a constant speed of 44 miles per hour relative to the water. The boat makes a trip upstream to a certai
serg [7]

Answer:

Step-by-step explanation:

Distance upstream = (34-c)(39/60) miles

--------------------------

Distance downstream = (34+c)(29/60) miles

-----------------------------------------------

Equation:

distance = rate*time

distance up = distance down

(34-c)(39/60) = (34+c)(29/60)

Multiply both sides by 60 to get:

39(34-c) = 29(34+c)

39*34 - 39c = 29*34 + 29c

68c = 340

c = 5 mph speed of the current

4 0
3 years ago
Each soda costs $4.50 at the baseball game. Which of the following represents the dependent variable?
Shkiper50 [21]

Answer:

The price of the soda.

Step-by-step explanation:

The dependent variable is the variable defined to be dependent on another object, typically the independent variable. That means the variable that varies based off of another value is the dependent variable. In this situation, as the number of sodas bought increases, the total price increases. The price varies off of the number of sodas because the increase in sodas causes it to increase. Thus, the price is the dependent variable.

8 0
3 years ago
I need help please someone
marta [7]

Answer:

B

Step-by-step explanation:

Earths resources are not distributed evenly, take other resources such as gold for example, you can't find gold everywhere, only in certain places.

4 0
3 years ago
What would be a equation for (5,2) and (0,7)?
Genrish500 [490]

\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{7}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{7}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{5}}}\implies \cfrac{5}{-5}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{-1}(x-\stackrel{x_1}{5}) \\\\\\ y-2=-x+5\implies y = -x+7

6 0
3 years ago
Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

3 0
3 years ago
Read 2 more answers
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