3. The graph f(x) = -x - is shown below.

A textbook store sold a combined total of 438 biology and psychology textbooks in a week. The number of psychology textbooks sol

Liono4ka [1.6K]

<h2>Answer:</h2>

Number of biology textbooks sold: 257 textbooks

Number of psychology textbooks sold: 181 textbooks

<h2>Explanations:</h2>

Let the total number of biology textbook sold be "a"

Let the total number of psychology textbook sold be "b"

If a textbook store sold a combined total of 438 biology and psychology textbooks in a week, then:

a + b = 438 ................... 1

If the number of psychology textbooks sold was 76 less than the number of biology textbooks sold, then;

b = a - 76 ...................... 2

Substitute equation 2 into 1

a + (a-76) = 438

a + a - 76 = 438

2a = 438 + 76

2a = 514

a = 514/2

a = 257 biology textbooks

From equation 2;

b = a - 76

b = 257 - 76

b = 181 psychology textbooks

Number of biology textbooks sold: 257 textbooks

Number of psychology textbooks sold: 181 textbooks

7 0

1 year ago

Iven that 1 9x x2 + 9 dx 0 = 30 10 − 81, what is 0 9u u2 + 9 du 1 ?

katrin [286]

Check the attached file for the solution.

5 0

3 years ago

Write the equation of the graph in vertex form enter power using ^ and don’t forget y or f(x)

enyata [817]

Me!!!! 245554! Then do 45316

8 0

3 years ago

In a newspaper poll concerning violence on television, 589 people were asked, "What is your opinion of the amount of violence on

abruzzese [7]

Answer:

(a) $P(Y'|M)\approx 0.3297$

(b) $P(Y|M')\approx 0.8323$

(c) $P(Y'|M')\approx 0.1323$

Step-by-step explanation:

Given table is

Yes No Don't Know Total

Men 162 92 25 279

Women 258 41 11 310

Total 420 133 36 589

According the the conditional probability, if A and B are two event then

$P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}$

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

$P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}$

$P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}$

$P(Y'|M)=\frac{92}{279}$

$P(Y'|M)=0.329749103943$

$P(Y'|M)\approx 0.3297$

(b)

$P(Y|M')=\frac{P(Y\cap M')}{P(M')}$

$P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}$

$P(Y|M')=\frac{258}{310}$

$P(Y|M')=0.832258064516$

$P(Y|M')\approx 0.8323$

(c)

$P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}$

$P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}$

$P(Y'|M')=\frac{41}{310}$

$P(Y'|M')=0.132258064516$

$P(Y'|M')\approx 0.1323$

5 0

3 years ago

A circular pond has a radius of 35 feet. What is the diameter of the pond?

SVEN [57.7K]

Answer:

I believe the radius is half the circle which makes the diameter 2x the radius which is 35+35= 70

4 0

2 years ago