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3 years ago

Complete the table of values for the proportional relationship.

Mathematics

1 answer:

Harrizon [31]3 years ago

6 0

Answer:

!) 10

Step-by-step explanation:

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Before simplifying, the expression 4 y - 6 + 4 y 2 - 9 contains three terms.

andre [41]

Yes it contains 3 terms

I hope this helps, good luck! :)

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3 years ago

If A⊥Y and X || Y, then _____

Mariana [72]

Answer:

A⊥X

Step-by-step explanation:

Since

A is perpendicular to Y

A⊥Y

And, X is parallel to Y

X || Y

Which means that they have the same slope (same inclination)

That implies that A must be also perpendicular to X

A⊥X

4 0

3 years ago

What is the slope of the line

nlexa [21]

Answer:

slope = -3/2

Step-by-step explanation:

It goes down 3, over 2.

Additionally, it is going down so it is negative.

Hope this helped! If you have any questions comment! :)

6 0

3 years ago

Read 2 more answers

How do you write an equation in slope-intercept form for the line with a slope 5 and y-intercept -5

noname [10]

Answer:

y=5x-5.

Step-by-step explanation:

slope-intercept form of a line is y = mx+b, where m is the slope and b is the y intercept. Simply plug in the numbers you get.

Thus, we get y = 5x-5.

8 0

3 years ago

There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b

WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

a>b>c

$a>b>c>d\\\implies x$

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together $=O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)$

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) $\frac{c}{3}$

Using (1)

$\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}$

Similarly

$\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}$

So,

$\frac{c}{3}$

3 0

3 years ago