Answer:
The total amount of fluids infused per day is 3,120 ml.
Step-by-step explanation:
Given that a patient is receiving a normal saline solution, infusing continuously at 80 ml / hr, and a tube feeding formula, Glucerna, infusing continuously at 50 ml / hr, to determine what is the total amount of fluids infused per day the following calculation must be done:
(80 x 24) + (50 x 24) = X
1,920 + 1,200 = X
3.120 = X
Therefore, the total amount of fluids infused per day is 3,120 ml.
Answer:
2abc
Step-by-step explanation:
●●●●○○○○□□□□■■■■
The last one as we can see that as the wight increases, the miles per gallon decreases.
Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) ![y=\frac{8}{2}=4](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B8%7D%7B2%7D%3D4)
a formula for the general term a n of the sequence assuming the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } is
.
<u>Step-by-step explanation:</u>
Here we have , the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } . We need to find a formula for the general term a n of the sequence . Let's find out:
In this question there is no such technique , instead we have to use our brain to manipulate the pattern as :
1st term = − 13/3 = ![(-1)^1\frac{13 }{3^{1}}](https://tex.z-dn.net/?f=%28-1%29%5E1%5Cfrac%7B13%20%7D%7B3%5E%7B1%7D%7D)
2nd term = 16/9 = ![(-1)^2\frac{13+3(1)}{3^2}](https://tex.z-dn.net/?f=%28-1%29%5E2%5Cfrac%7B13%2B3%281%29%7D%7B3%5E2%7D)
3rd term = − 19/27 = ![(-1)^3\frac{13+3(2)}{3^3}](https://tex.z-dn.net/?f=%28-1%29%5E3%5Cfrac%7B13%2B3%282%29%7D%7B3%5E3%7D)
4th term = 22/81 = ![(-1)^4\frac{13+3(3)}{3^4}](https://tex.z-dn.net/?f=%28-1%29%5E4%5Cfrac%7B13%2B3%283%29%7D%7B3%5E4%7D)
5th term = − 25/243 = ![(-1)^5\frac{13+3(4)}{3^5}](https://tex.z-dn.net/?f=%28-1%29%5E5%5Cfrac%7B13%2B3%284%29%7D%7B3%5E5%7D)
nth term = ![(-1)^n\frac{13+3(n-1)}{3^n}](https://tex.z-dn.net/?f=%28-1%29%5En%5Cfrac%7B13%2B3%28n-1%29%7D%7B3%5En%7D)
Therefore, a formula for the general term a n of the sequence assuming the pattern of the first few terms continues. { − 13/3 , 16/9 , − 19/27 , 22/81 , − 25/243 , ... } is
.