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masya89 [10]
3 years ago
5

Which of these values represents the largest distance?

Mathematics
2 answers:
GarryVolchara [31]3 years ago
7 0

Answer:C 5000 feet

Step-by-step explanation:It’s slightly less then a mile.

pshichka [43]3 years ago
4 0

Answer:

<h2>C. 5,000 feet </h2>

Step-by-step explanation:

First of all, you would want to convert all of the distances into the same units.

Let's convert the distances to miles.

5,000 inches = about 0.08 miles

0.5 miles = 0.5 miles

5,000 feet = about 0.9 miles

500 yards = about 0.3 miles

Now, we compare the values.

We can easily place 5,000 inches last, because when converted to miles it's 0.08.

0.08<0.3<0.5<0.9

5,000 inches<500 yards<0.5 miles<5,000 feet

Hence, the answer is C.

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A truck can travel 80 miles in the same time that ot takes a car to travel 90 miles. If the truck’s rate is 5 miles per hour slo
SIZIF [17.4K]
The truck was going 40 miles per hour

The amount of time was 2 hours:
(90-80: 10)(10/2=5)

80 divided by two is 40


The car was going 45 miles per hour


(90-80:10)(10/2=5)

90 divided by two is 45


Hopefully you find this helpful
3 0
3 years ago
Simplify the following expressions. Put your a<br> (3x³-5x² - 7+ 4x4) + (9x4 - 10x² - 5x³ + 3) =
leonid [27]

first we need to get rid of the ( ) so that we can see what the question really says

(3x³-5x² - 7+ 4x4) + (9x4 - 10x² - 5x³ + 3)

= 3x³-5x²-7+4x⁴+9x⁴-10x²-5x³+3

now all we need to do is add up the numbers with the same x's

<em>3x³</em>-5x²-7<u>+4x⁴+9x⁴</u>-10x²<em>-5x³</em>+3

= 13x⁴-2x³-15x²-4

6 0
2 years ago
Simplify the following expressions using Order of Operations.<br><br> 4+ 8 = 2 + 6 x 2
Hunter-Best [27]

Answer:

12 ≠ 14

Step-by-step explanation:

(4+8)=2+(6x2)

12 = 2 + 12

12 ≠ 14.

So the equation is false.

4 0
3 years ago
Tia is 8 years younger than her sister Annette. Annette is y years old. Write an algebraic expression that describes Tia’s age.
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8-y
Hope this helps and please mark brainliest.
6 0
3 years ago
Read 2 more answers
A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,
Andru [333]

Answer:

A. Null and alternative hypothesis:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848

The degrees of freedom for this sample size are:

df=n-1=42-1=41

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=2\cdot P(t>4.848)=0.00002

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.02 \cdot 173.283=350

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190

The 95% confidence interval for the mean difference is (490, 1190).

7 0
3 years ago
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