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masya89 [10]
4 years ago
5

Which of these values represents the largest distance?

Mathematics
2 answers:
GarryVolchara [31]4 years ago
7 0

Answer:C 5000 feet

Step-by-step explanation:It’s slightly less then a mile.

pshichka [43]4 years ago
4 0

Answer:

<h2>C. 5,000 feet </h2>

Step-by-step explanation:

First of all, you would want to convert all of the distances into the same units.

Let's convert the distances to miles.

5,000 inches = about 0.08 miles

0.5 miles = 0.5 miles

5,000 feet = about 0.9 miles

500 yards = about 0.3 miles

Now, we compare the values.

We can easily place 5,000 inches last, because when converted to miles it's 0.08.

0.08<0.3<0.5<0.9

5,000 inches<500 yards<0.5 miles<5,000 feet

Hence, the answer is C.

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1) yes

2) No

3) No

4) yes

5) No

Step-by-step explanation:

1) f(0)=0, f(1)=1, f(2)=2, f(3)=3, then f[\{0, 1, 2, 3\}]=\{0, 1, 2, 3\}

2) f(0)=0, 1^2=1\equiv 1 \text{mod 4}, then f(1)=1; 2^2=4\equiv 0 \text{ mod 4}, then f(2)=0; 3^2=9\equiv 1 \text{mod 4}, then f(3)=1

Then f[\{0, 1, 2, 3\}]=\{0, 1, 3\}, this means that f isn't onto.

3.

  • f(0)=0;
  • 1^1-1=0, then f(1)=0
  • 2^2-2=2, then f(2)=2
  • 3^2-3=6\equiv 2 \text{ mod 4}, then f(3)=2

Then  f[\{0, 1, 2, 3\}]=\{0, 2\}, this means that f isn't onto.

4.  f[\{0, 1, 2, 3\}]=\{0, 1, 2,3\}, then f is onto.

5. f[\{0, 1, 2, 3\}]=\{1, 2\}, this means that f isn't onto.

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