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son4ous [18]
3 years ago
15

I need a 10 squared root chart

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

here you gooo
you can just copy this 
this is the exact squared root chart

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I NNEEEDDDDDD HELPPPPP PLEASEEEE
NikAS [45]

Answer:

The small balloon bouquet uses  7 balloons and the large one uses

18 balloons.

Step-by-step explanation:

Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:

6S + 6L= 150

S+L= 25   ----> 1st equation

For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:

6S + 1L= 60

1L= 60- 6S   ----> 2nd equation

We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:

S+L = 25

S+ (60-6S)= 25

-5S= 25-60

-5S= -35

S= -35/-5

S=7

Then we can find L by substitute S value to 1st or 2nd equation.

S+L=25

7+L=25

L=18

Hope this helps ;)

3 0
3 years ago
Read 2 more answers
Solve for x<br><br> 4x + 7 + 3x = 19 + x
IceJOKER [234]
7x-x=19-7
6x=12
x=2
Ask me if you have a question. Glad to help!! :))
6 0
2 years ago
What is the slope of the line​
lidiya [134]

Answer:

c is the correct answer

Step-by-step explanation:

because i worked it out

8 0
2 years ago
Read 2 more answers
What is the radius of a circle whose equation is x2 + (y – 8)2 = 25?
Dafna11 [192]
Use photo math :) and you will get your answer
8 0
3 years ago
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Can you answer this question as soon as possible.
Whitepunk [10]

Answer:

The intensity of the first earthquake is 6.31 times the second one

Step-by-step explanation:

The given formulae is M=log(\frac{I}{S})

Here for both the earthquakes the value of S is same.

Let the Intensity of the first earthquake be I1 and the second be I2.

Given M1=7.5

M2=6.7

Now  M1=log(\frac{I1}{S})------1

M2=log(\frac{I2}{S})-----2

Now subtract 1 and 2 we get

M1-M2=log(\frac{I1}{I2})

I1/I2=10^{M1-M2}

I1=I2(10^{0.8}

I1=I2*6.31

6 0
2 years ago
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