Answer:
The correct answer is 0.26 M
Explanation:
The initial concentration of NaCl solution (Ci) is 5.0 M. The initial volume of the solution (Vi) is 13 mL. The final volume is the addition of 240 mL to 13 mL (Vf= 13 mL + 240 mL= 253 mL).
In order to calculate the final concentration of the solution (Cf) we can use the following expression:
Ci x Vi= Cf x Vf
This mathematical expression is often used to calculate concentrations in dilution procedures. So, we introduce Ci, Vi an Vf in the expression and we calculate Cf:
Cf= (Ci x Vi)/Vf= (5.0 M x 13 mL)/253 mL= 0.257 M ≅ 0.26 M
Are u using a punnet square for children or for genotypes
Answer:
D. DDT
Explanation:
DDT is highly persistent in the environment means that it break down very slowly in the environment. The half-life for DDT is from 2 to 15 years. Half-life is the time needed for the degradation of half of the compound. Persistent bio-accumulative toxic substances (PBTs) are chemicals that break down slowly in the environment and its accumulation in living organisms are toxic. Some PBTs are dispersed through air currents while some uses other environmental pathways, resulting in contamination of regions far from their points of origin.
A.The genotype frequencies can be determined by dividing the number of individuals with a genotype by the total number all the individuals.
FF genotype frequency:
98÷200=0,49. There are approximately 5 <span>homozygous dominant mice in 10.
Ff genotype frequency:
84</span>÷200=0,42. There are approximately 4 <span>heterozygous mice in 10.
ff genotype frequency:
18</span>÷200=0,09. There are approximately 1 <span>homozygous recessive mouse in 10.
B.To determine the frequency of an allele we can divide the number of times that the allele appears by the total number of alleles.
F allele frequency:
</span>

<span>=0.7
There are 7 F alleles in 10 random alleles.
f </span>allele frequency:

=0.3
There are 3 f alleles in 10 random alleles.<span>
</span>
Answer D) : from testing the starch by iodine