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2 years ago

Please help me answer this

Mathematics

1 answer:

salantis [7]2 years ago

4 0

Do you need an explanation or just the answer ???? (32/7,-6/7)

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Copy the shape and fill in the missing angle. Sow the work. Thanks.

Otrada [13]

Answer:

x = -11

Step-by-step explanation:

Hello There!

create an equation

x + 51 + 60 + 80 = 180

combine like terms

51 + 60 + 80 = 191

x + 191 = 180

subtract 191 from each side

180 - 191 = -11

we're left with

x = -11

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2 years ago

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Dovator [93]

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aliya0001 [1]

Answer:

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Step-by-step explanation:

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Elis [28]

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2 years ago

Read 2 more answers

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

ddd [48]

Answer:

$f'(x) = 4x^2 - 3$ for $x \le -3$

Step-by-step explanation:

See attachment for proper question

Given

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

For

$x \ge -3$

Required

Determine the inverse function

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

Replace f(x) with y

$y = -\frac{1}{2}\sqrt{x + 3}$

Swap the positions of x and y

$x = -\frac{1}{2}\sqrt{y + 3}$

Multiply both sides by -2

$-2 * x =-2 * -\frac{1}{2}\sqrt{y + 3}$

$-2x =\sqrt{y + 3}$

Square both sides

$(-2x)^2 =(\sqrt{y + 3})^2$

$4x^2 =y + 3$

Make y the subject

$y = 4x^2 - 3$

The inverse has been solved. So, we need to replace y with f'(x)

$f'(x) = 4x^2 - 3$

Next, is to determine the interval

$x \ge -3$

Change inequality to $\le$

$x \le -3$

Hence, the inverse function is:

$f'(x) = 4x^2 - 3$ for $x \le -3$

7 0

2 years ago