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3 years ago

Can someone please help me with this geometry problem?

Mathematics

2 answers:

Anastasy [175]3 years ago

5 0

I don't know that we can help you without more info.
Do you have a photo of the problem that you could upload?

aleksklad [387]3 years ago

4 0

1. ray BF bisects ∠ABC 1. given

m∠ABD = m∠CBE

2. ∠ABF ≅ ∠ CBF 2. angle bisector theorem

3. m∠ABF = m∠CBF 3. definition of congruency

4. m∠ABF = m∠ABD + m∠DBF 4. angle addition postulate

m∠CBF = m∠CBE + m∠EBF

5. m∠ABF = m∠CBE + m∠DBF 5. substitution (s1: m∠ABD = m∠CBE)

6. m∠CBF = m∠CBE + m∠DBF 6. substitution (s3: ∠ABF = ∠ CBF)

7. m∠CBE + m∠DBF = m∠CBE + m∠EBF 7. transitive property

8. m∠DBF = m∠EBF 8. subtraction property

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Can a triangle be formed with the sides lengths of 8 cm, 5 cm and 13 cm?

Anni [7]

The rule says that the sum of any two sides has to be smaller than the third side so, no it can't

4 0

3 years ago

A certain hybrid car has a mileage rating of 57 miles per gallon. if the car makes a trip of 293 miles, how many gallons of gaso

dlinn [17]

To determine the number of gallons of gasoline that is used, we need to know the rate of usage of gasoline. This rate would describe the number of gasoline in units of volume that is being used per distance in units of length. In this case, we need the rate in units of miles per gallon. From what is asked and the given values, we simply divide the rate to the the total distance that was traveled by the car. We calculate as follows:

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4 0

3 years ago

Solve (x+y) if x=-1/2 and y=-3

bixtya [17]

Answer:

$-3\frac{1}{2}$

Step-by-step explanation:

Solve

$(x+y)$

For x=-1/2 and y=-3

substitute the value of x and the value of y in the expression above

$x+y=(-\frac{1}{2})+(-3)$

Remember that

$(+1)(-1)=-1$

$x+y=-\frac{1}{2}-3=\frac{-1-6}{2}=-\frac{7}{2}$

Convert to mixed number

$-\frac{7}{2}=-\frac{6}{2}-\frac{1}{2}=-3\frac{1}{2}$

7 0

3 years ago

PLEASE HELP

Mumz [18]

If you use/make a number line, then you will see that the answer is -18 or a. When using a number line, negative = ← and positive = →.

6 0

3 years ago

find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}

inn [45]

Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2 and x" = [10 - √64]/2

x' = (10+12)/2 and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity

6 0

3 years ago