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katrin [286]
3 years ago
7

Can someone please help me with this geometry problem?

Mathematics
2 answers:
Anastasy [175]3 years ago
5 0
I don't know that we can help you without more info.
Do you have a photo of the problem that you could upload?
aleksklad [387]3 years ago
4 0

1. ray BF bisects ∠ABC                   1. given

   m∠ABD = m∠CBE              

2. ∠ABF ≅ ∠ CBF                            2. angle bisector theorem

3. m∠ABF = m∠CBF                        3. definition of congruency

4. m∠ABF = m∠ABD + m∠DBF       4. angle addition postulate

  m∠CBF = m∠CBE + m∠EBF

5. m∠ABF = m∠CBE + m∠DBF      5. substitution (s1: m∠ABD = m∠CBE)

6. m∠CBF = m∠CBE + m∠DBF       6. substitution (s3: ∠ABF = ∠ CBF)

7. m∠CBE + m∠DBF = m∠CBE + m∠EBF   7. transitive property

8. m∠DBF =  m∠EBF                        8. subtraction property

 

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3 years ago
Need help quick please
valina [46]

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Step-by-step explanation:

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What are the zeros of the function below? F(x)= (x-1)(x+1)/6(x-4)(x+7)
Lisa [10]

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+1 and -1

Step-by-step explanation:

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f(x)=\frac{(x-1)(x+1)}{6(x-4)(x+7)}

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In order to find the domain, we have to require that the denominator is different from zero, so

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Now we can solve the problem and find the zeros of the function. The zeros can be found by requiring that the numerator is equal to zero, so:

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3 years ago
Identify the two triangle congruence criteria that do NOT guarantee congruence. Explain why they do not guarantee congruence, an
Mashcka [7]

Answer: Hello mate!

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AAA ( or 3 angles)

two triangles can have the same 3 angles, but different size, then they are not congruent; an example of this is:

take the triangle rectangle of both cathetus = 1 and hypotenuse = √2, where the angles are 90°, 45° and 45°

and now take the triangle rectangle with both cathetus = 2 and hypotenuse = √8, this triangle also has the angles 90°, 45°, and 45°, so this two triangles succeed the AAA criteria, but are not congruent.

SSA (side-side-angle)

If two triangles satisfy the SSA  criteria and the corresponding angles are acute and the length of the side opposite to the angle is greater than the length of the adjacent side multiplied by the sine of the angle (but less than the length of the adjacent side), then the two triangles are not necessarily congruent.

This is kinda harder to illustrate;  

think on a triangle rectangle where you have the measure of both cathetus and one of the angles different from 90° as the SSA data.

and now think on another triangle that has the same adjacent cathetus and angle, and where the other cathetus is rotated (in a sense where 90° is decreasing) to the point where its tip intercepts the hypotenuse of the first triangle.

Those two triangles meet the SSA criteria but are not congruent.

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