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3 years ago

Solving 12-(x+3)=10

1 answer:

4 0

12-(x+3)=10

Simplify the equation.

12-x-3=10

Combine like terms.

(12-3)-x=10

Simplify.

9-x=10

Subtract 9 from both sides to get x by itself.

-x=1

Divide both sides by -1 to get x by itself.

x=-1

~Hope I helped!~

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a bathtub in the shape of a rectangular prism is 5 feet long, 3 1/2 feet wide, and 4 1/4 feet high. How much water could the tub

kondaur [170]

The tub could hold 74 and 3/8

6 0

3 years ago

Solve i + j + t (3i - j) = -i + s (j)<br> In the context of Vector Equations of a Line

Oksana_A [137]

Answer:

r = i + j + (-2/3)(3i - j)

Step-by-step explanation:

Vector Equation of a line - r = a + kb ; where r is the resultant vector of adding vector a and vector b and k is a constant

if a = i + j ; b = t(3i - j) and r = -i +s(j)

for this to be true all the vector components must be equal

summing i 's

i + 3ti = -i; then t = -2/3

j - tj = sj; then s = 1-t; substitue t; s=1+2/3 = 5/3

so r = i + j + (-2/3)(3i - j) which will symplify to -i + 5/3j

3 0

2 years ago

You have $120 in your checking account. In one month, you deposit $30, write a check for $21, withdraw $20, and deposit $45. Fin

gizmo_the_mogwai [7]

Answer:

Your total balance is 154.

Step-by-step explanation:

You start with 120.

+30

-21

+45

Hope that helps.

4 0

3 years ago

Read 2 more answers

Please help me graph

Anika [276]

(x, y) = (-3, 4) hope this helps!

6 0

3 years ago

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

3 years ago