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⭐Here is Your Answer...!!!
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↪SURFACE AREAS AND VOLUMES
↪The VOLUME of any object is nothing but the the capacity to hold the amount of substance inside it . It defines the Amount of substance that can occupied bythe object inside it ..
↪Volume = Base Area × Height
↪thus for the Cylinder ; Volume of cylinder = Pi(R^2) × H
↪thus volume = 3.14 × R^2 × H
↪thus here given as R = 4 cm and H = 12cm
↪Volume = 3.14 × 16 × 12= 602.88 cm^3
thus
↪the Volume of the Cylinder = 602.88 cm^3
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Answer:
x = -3 + 2 i or x = -3 - 2 i
Step-by-step explanation:
Solve for x:
x^2 + 6 x + 13 = 0
Hint: | Solve the quadratic equation by completing the square.
Subtract 13 from both sides:
x^2 + 6 x = -13
Hint: | Take one half of the coefficient of x and square it, then add it to both sides.
Add 9 to both sides:
x^2 + 6 x + 9 = -4
Hint: | Factor the left hand side.
Write the left hand side as a square:
(x + 3)^2 = -4
Hint: | Eliminate the exponent on the left hand side.
Take the square root of both sides:
x + 3 = 2 i or x + 3 = -2 i
Hint: | Look at the first equation: Solve for x.
Subtract 3 from both sides:
x = -3 + 2 i or x + 3 = -2 i
Hint: | Look at the second equation: Solve for x.
Subtract 3 from both sides:
Answer: x = -3 + 2 i or x = -3 - 2 i
17/4 + 17/4 + 17/4 = 51/4 cups
51/4 = 12 3/4 cups
Answer:
10 km
Step-by-step explanation:
volume of cube = s^3
1 m = 100 cm
volume = s^3 = (1 m)^3 = (100 cm)^3 = 1,000,000 cm^3
Since 1 m^3 = 1,000,000 cm^3, when you lay down the 1-cm cubes in a straight line with the edges touching, the line is 1,000,000 cm long.
1,000,000 cm = 10,000 m = 10 km
Answer:
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
Step-by-step explanation:
In this problem we have a normal ditribution with mean of 4.0 in and standard deviation of 1.5 in.
The proportion of the trees that are expected to have diameters greater than 5 inches is equal to the probability of having a tree greater than 5 inches.
We can calculate the z value for x=5 in and then look up in a standard normal distribution table the probability of z.
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
