For this case we have that the volume of the figure is composed of the volume of a prism and the volume of a pyramid:
The volume of the prism is given by:

Where:
: It is the area of the base
h: It's the height
Substituting:
The volume of the pyramid is given by:

Where:
It is the area of the base
h: It's the height
Substituting:

We add and we have:

ANswer:
Option D
Answer:
Have a splendiferous day...
Step-by-step explanation:
3÷12=¼
6÷10=⅗
7÷14=½
10÷11=⅚
2÷4=½
4÷16=¼
3÷24=⅛
18÷54=⅓
D) i think
, all values of x that are greater than equal to 1
7
8
Answer:
i. 6
ii. 
iii. 7
Step-by-step explanation:
First organize the data from least to greatest. 3,3,4,5,6,7,7,7,8
To find the median, remove the extremes from the data over and over.
3,4,5,6,7,7,7
4,5,6,7,7
5,6,7
6
To find the mean, add all of the numbers and divide by 9
3+3+4+5+6+7+7+7+8=50
50/9=
To find the modal mark, simply find the number present most in the data set: 7(occurs 3 times)
Hope it helps <3