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Lera25 [3.4K]
3 years ago
6

The radioactive element carbon-14 has half of 5750 years. A scientist determined that the bones from a mastodon has lost 56.6% o

f their carbon-14. How old were the bones at the time they were discovered?
Mathematics
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:7881 years

Step-by-step explanation:

You can use the equation

fraction remaining = 0.5n where n is # of half lives elapsed

n = ?

fraction remaining = 1 - 0.612 = 0.388

0.388 = 0.5n

n = 1.37 = the # of half lives

1.37 x 5750 yrs = 7881 years

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Evgesh-ka [11]

Answer:Null hypothesis:  

Alternative hypothesis:  

 

 

The p value obtained was a very high value and using the significance level given  we have  so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of orders that were not accurate is not significant different from 0.1 or 10% .  

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Step-by-step explanation:

Data given and notation n  

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X=32 represent the orders that were not accurate

estimated proportion of orders that were not accurate

is the value that we want to test

represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

 

Alternative hypothesis:  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

(1)  

The One-Sample Proportion Test is used to assess whether a population proportion  is significantly different from a hypothesized value .

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

 

Statistical decision  

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The significance level provided . The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

 

So the p value obtained was a very high value and using the significance level given  we have  so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of orders that were not accurate is not significant different from 0.1 or 10% .  

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