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den301095 [7]
1 year ago
7

The length of each side is quadrupled. How many times larger is the new area when compared to the original?

Mathematics
1 answer:
GaryK [48]1 year ago
5 0

16 times larger is the new area when compared to the original.

Given that, the length of each side of the square is quadrupled.

We need to find how many times larger is the new area when compared to the original.

<h3>What is the area of a square?</h3>

A square is a closed two-dimensional shape with four equal sides and four equal angles. The four sides of the square form the four angles at the vertices. The sum of the total length of the sides of a square is its perimeter, and the total space occupied by the shape is the area of the square. The formula to calculate the area of a square is a².

Let the length of each side of the square be x.

Then the length of each side of the new square will be 4x.

Now, the area of the original square = x²

The area of the new square = (4x)² = 16x²

So, the new square = 16 × the original square

Therefore, 16 times larger is the new area when compared to the original.

To learn more about the area of a square visit:

brainly.com/question/1561162.

#SPJ1

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Step-by-step explanation:Start by writing like this below

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Maru [420]

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  in order to keep the same gross margin, you need to increase the sale price by 25%

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HELPPPPP PLZZZZ<br> What real number a and b make the equation true?<br> (a-3)+(b+8)i=3-4i
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Step-by-step explanation:

In complex number algebra, you need to sum the real values with each others and the imaginary values with each others.

In order to determine which number is a real value and which one is an imaginary, we must expand the parenthesis terms:

(a-3) + (b+8)i =a - 3 + bi + 8i = 3 - 4i

Now we match real numbers with real numbers and imaginary numbers with imaginary numbers:

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Usually now, the interest is added onto the principal to figure some new amount after 3 month(s),
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