JAVA programming was employed...
What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules
Solution:
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:
x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement
Answer:
It's due to damage of goods
Answer: C. although a rainy day (A) would make it more aesthetic
Answer:
Program approach:-
- Using the header file.
- Using the standard namespace I/O.
- Define the main function.
- Display the number of terms.
- Display the Fibonacci series.
- Print the first two numbers.
Explanation:
Program:-
//header file
#include <iostream>
//using namespace
using namespace std;
//main function
int main() {
int n, s1 = 0, s2 = 1, nextTerm = 0;
//display the number of terms
cout << "Enter the number of terms: ";
cin >> n;
//display the Fibonacci series
cout << "Fibonacci Series: ";
for (int j = 1; j <= n; ++j) {
// Prints the first two terms.
if(j == 1) {
cout << s1 << ", ";
continue;
}
if(j == 2) {
cout << s2 << ", ";
continue;
}
nextTerm = s1 + s2;
s1 = s2;
s2 = nextTerm;
cout << nextTerm << ", ";
}
<span>Good Posture – Trish should look
for a good ergonomic chair that will help with her aches. She should identify her natural posture and
memorize it.</span>
<span>Regular movement and work
organization – Encourage regular breaks and stretch or walk around the office. At least once an hour is recommended.</span>
Position of the screen – Trish should
consider factors such as distance, height, and angle of the screen.
