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Margarita [4]
3 years ago
6

Which of these is NOT an example of lifelong learning?

Computers and Technology
1 answer:
oee [108]3 years ago
7 0

Answer:

B. having lunch with a friend

Explanation:

Lifelong learning can be defined as a continuous, self-motivated, and self-initiated learning activity that is typically focused on personal or professional development. Thus, it's a form of education that is undertaken throughout life with the sole aim of pursuing knowledge, competencies, and skills for either personal or professional growth and development, especially after acquiring a formal education.

Some examples of lifelong learning includes the following;

I. Reading a trade magazine.

II. Reviewing a textbook.

III. Studying an encyclopedia.

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Each student has a record on a file consisting of the following data: Student last name, Student ID (numeric), GPA (a decimal nu
slavikrds [6]

Answer:

#include<iostream>

using namespace std;

struct student {

   string name;

   int id;

   float gpa;

   int major;

};

int main() {

   student student1;

   student1.name="Patil";

   student1.id=1;

   student1.gpa=9.80;

   student1.major=123;

   cout<<"First student last name: "<<student1.name;

}

Explanation:

A struct is a container or data structure in C and C++ that holds data that describes or represents an object. It is defined with the struct keyword. Just like a class constructor method, the struct is called with the struct name and the instance name of the struct.

The student struct above is used to create an instance of students registered in a school. The first student struct instance is the 'student1'.

7 0
3 years ago
Which of these ia an example of gene flow?
GalinKa [24]

In population genetics, gene flow (also known as gene migration) is the transfer of alleles or genes from one population to another. Migration into or out of a population may be responsible for a marked change in allele frequencies (the proportion of members carrying a particular variant of a gene).

7 0
3 years ago
What is a circular network.​
Travka [436]

Answer:

A circular network happens when you have two (or more) routes to the same controller. Typically, the routes are BACnet/IP and BACnet/Ethernet and both are communicating on both networks. This could happen with BACnet MS/TP although it is rare.

Explanation:

5 0
2 years ago
Read 2 more answers
Below you will find the requirements to identify the Account Diversity Grade of a user. Read the requirements carefully and iden
igomit [66]

The technique I used to test the requirement is equivalence partitioning.

<h3>Equivalence Partitioning-</h3>

Generic test data is considered where all the test data satisfies the conditions provided in the problem. Such that,

- ADGrade A --> TA=25 LC=5

- ADGrade B --> TA=20, LC=3

- ADGrade C --> TA=8 LC=2

- ADGrade D --> TA=2, LC=1

- ADGrade null (n/a)—> TA=0, LC=0

Where:

  • TA represents totalAccounts,
  • LC represents loanTypeCount,
  • ADGrade represents accountDiversityGrade

If we are to combine the test data collected above, we would obtain the entire set of test data.

With this in mind, the minimum number of users that are required for testing the requirement is 5.

Read more about requirement testing here:

brainly.com/question/16147055

#SPJ1

8 0
1 year ago
The monkey-and-bananas problem is faced by a monkey in a laboratory with some bananas hanging out of reach from the ceiling. A b
elixir [45]

Answer:

a) <u>initial state description</u>

<em>At(Monkey, A) ∧ At(Bananas, B) ∧ At(Box, C) ∧</em>

<em>Height(Monkey, Low) ∧ Height (Box, Low) ∧</em>

<em>Height (Bananas, High) ∧ Push(Box) ∧ ClimbUp(Box)</em>

b)  <u>the six action schemas.</u>

1 - Go from one place to another

<em>Action (Go(x, y),</em>

<em>PRECONDITION: At (Monkey, x)</em>

<em>EFFECT: At (Monkey, y) ∧¬At(Monkey, x))</em>

2 - Push an object from one place to another

<em>Action (Push(b, x, y),</em>

<em>PRECONDITION: At (Monkey, x) ∧ Can Push(b)</em>

<em>EFFECT: At(b, y) ∧ At (Monkey, y) ∧¬At(b, x) ∧¬At(Monkey, x))</em>

3 - Climb up unto an object

<em>Action (ClimbUp(b),</em>

<em>PRECONDITION: At(b, x) ∧ At(Monkey, x) ∧ ClimbUp(b)</em>

<em>EFFECT: On (Monkey, b) ∧¬Height (Monkey, High))</em>

4 - ClimbDown from an object

<em>Action (ClimbDown (b),</em>

<em>PRECONDITION: On (Monkey, b) ∧ Height (Monkey, High)</em>

<em>EFFECT: ¬On (Monkey, b) ∧¬Height (Monkey, High) ∧ Height(Monkey, Low))</em>

5 - Grasp an object

<em>Action (Grasp (object, position, height),</em>

<em>PRECONDITION: Height(Monkey, h) ∧ Height(b, h) ∧ At(Monkey, x) ∧ At(b, x)</em>

<em>EFFECT: Has(Monkey, b))</em>

6 - Ungrasp an object

<em>Action (Ungrasp(b),</em>

<em>PRECONDITION: Have(Monkey, b)</em>

<em>EFFECT: Has(Monkey, object))</em>

<em />

c) <u>general goal state.</u>

<em>Has(Monkey, Bananas, s) ∧ (ЗхAt(Box, x, s₁) ∧ At(Box, x, s))</em>

STRIPS only consider about goal state, there is no relation between two states within the plan, so there is no way to represent this goal.

6 0
4 years ago
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