Which transformations could have taken place to
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To be able to compare 2 fraciton we have to make common denominator and then we can just compare numerators.
Now we can compare numerator from the first (9) and from the second fraction (8)
9>8, so the bigger is 9/10
Now we can compare numerator from the first (9) and from the second fraction (8)
9>8, so the bigger is 9/10
To obtain x, we can sum the angles < AQB and < BQC
=> 5X + 8X - 24
=> 13X -24
we are also told that that the sum of their angles is 80
13X - 24 = 80
13 X = 24 + 80
13X = 104
Divide both sides by 13
x = 104/13
x = 8
