Answer:
r = 225 Mil/h speed of the airplane in still air
Step-by-step explanation:
Then:
d is traveled distance and r the speed of the airplane in still air
so the first equation is for a 4 hours trip
as d = v*t
d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)
Second equation the trip back in 5 hours
d = 5 * ( r - 25 ) (2)
So we got a system of two equation and two unknown variables d and
r
We solve it by subtitution
from equation (1) d = 4r + 100
plugging in equation 2
4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h
And distance is :
d = 4*r + 100 ⇒ d = 4 * ( 225) + 100
d = 900 + 100
d = 1000 miles
Answer:
- 1.67
Step-by-step explanation:
f(x) = 
- 
= 
- 
= 
- 2
= - 1 
= -1.6666666
= -1.67
Answer:
Please see attached picture for full solution.
Sorry, I'm not sure how to do Q7 :(
Answer:
BC = 11
Step-by-step explanation:
using the sine ratio in the right triangle and the exact value
sin45° = 
, then
sin 45° = 
= 
= 
= ( cross- multiply )
BC = 11
32,870 is the answer. Hope this helps!
