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IRINA_888 [86]
3 years ago
11

What is the first step for managing innovation during discontinuous change?

Biology
1 answer:
algol [13]3 years ago
3 0
The design iteration.
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The hygrometer must be calibrated before it is used. How might this be done?
kakasveta [241]
Place a teaspoon of salt in a bottle cap or small cup and dampen it with a few drops of water (without dissolving it). Carefully place the wet salt and the hygrometer inside a see-through container and close tightly. You can use a zip lock bag provided it seals well and you leave some air inside as well
8 0
3 years ago
A squid moves through the water by ejecting water out of its body into the surrounding water when the water is pushed out the ej
dusya [7]

Answer:

The answer is Inertia

Explanation:

when the squid is pushing the water is pushing back at the squid, and the third law of inertia states:That for every action there is an equal and opposite reaction. so the squid is pushing the opposite way and the water pushes back.

4 0
3 years ago
BRAINLIEST AND 50 POINTS TO FIRST CORRECT ANSWER
Studentka2010 [4]

Answer:

t has four stages known as glycolysis, Link reaction, the Krebs cycle, and the electron transport chain. This produces ATP which supplies the energy that cells need to do work. When they don't get enough oxygen, the cells use anaerobic respiration, which doesn't require oxygen

Explanation:

;

6 0
4 years ago
List at least two possible reasons for the differences you see between the pinch strength of the first two fingers and the secon
andriy [413]

Answer:

The first two fingers may be stronger due to the fact that they are used the most often and could build up more strength and dexterity. Another reason the first two fingers may be stronger could be due to the fact that the ulnar muscle that controls digits 4 and 5 is smaller than the radial muscle.

Explanation:

Pinch strength is a widely used measurement of hand function. A direct relationship between pinch strength and function has been demonstrated and illustrates the importance of hand strength in clinical practice.There is a difference in grip strength in the dominant and non-dominant hands.Dominant hand  is significantly stronger. According to the pinch strength data, he index finger and the thumb are the strongest, the middle finger and the thumb are the second strongest, the ring finger and the thumb are the third strongest, and the little finger and the thumb are last. The difference is the largest between the middle finger and the thumb and the ring finger and the thumb.

The first two fingers may be stronger due to the fact that they are used the most often and could build up more strength and dexterity. Another reason the first two fingers may be stronger could be due to the fact that the ulnar muscle that controls digits 4 and 5 is smaller than the radial muscle.

Difference in the pinch strength may be due to one possible reason that the radial muscle is larger than the ulnar muscle which controls digits 4 and 5. Another reason could be that you generally use the thumb, index, and middle fingers more than the ring and little finger, therefore the first three fingers have more strength and muscle memory.

8 0
4 years ago
A population of Muscovy ducks contains 13 birds with black masks and 37 birds with red masks. Red masks are the dominant trait.
Semmy [17]

Answer: Black allele has frequency of 0.14.

              Red allele has frequency of 0.86.

             The frequency of heterozygotes is 0.241

Explanation: <em>Hardy-Weinberg model </em>states the frequency of alleles in a population will stay in equilibrium as long as there are external influences. It is also used to determine alleles frequencies using the following equations:

p+q=1

p^{2}+2pq+q^{2}=1

p represents frequency of dominant allele;

q represents frequency of recessive allele;

2pq is frequency of heterozygotes;

For the frequency of red allele, which is dominant, we can use:

p^{2}=\frac{37}{13+37}

p^{2}=\frac{37}{50}

p^{2}=0.74

p=\sqrt{0.74}

p = 0.86

For the black allele:

p+q=1

q=1-p

q=1-0.86

q = 0.14

Frequency of heterozygotes is

2pq = 2(0.86)(0.14)

2pq = 0.241

<u>Frequencies for a population of Muscovy ducks are </u><u>0.86 for red allele, 0.14 for black allele and 0.241 for heterozygote.</u>

5 0
3 years ago
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