Cystic fibrosis is a recessive condition; meaning if a
dominant condition takes over it will not be seen in the offspring. The man
genotype with cystic fibrosis can only be this: cc (when c is equal to the cystic fibrosis and C is equal to not
having one). The woman with no history of cystic fibrosis can possibly have
either of these two genotypes: Cc or CC.
To see their offspring’s possible genotype, we’ll use a
punnett square let’s start with Cc:
C c
c Cc cc
c Cc cc There
is a 50 % chance of the child having cystic fibrosis.
To see their offsprings possible genotype with CC:
C C
c Cc Cc
c Cc Cc There
is no chance that the child will have cystic fibrosis.
Answer:
50% BB (black), and 50% Bb (black)
Explanation:
When you make the punnet square, you will get two BB, and two Bb. That will show you that the outcome of all the offspring will be black. There is 0% chance there will be a grey mouse because it is the recessive gene.
False?, it more or less goes on the amounts of abortions the more you get the more chances you'll become infertile,
The answer is either 75% or 100% I hope this helped you at least a little bit my best guess would be 100%
Answer:
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