Question

An activity on a PERT network has these time estimates: optimistic =2, most likely = 3, and pessimistic 8. Its expected time and variance (if it is a critical activity) are:_______

Answer 1

Answer:3.67,1

Explanation:

TE = (O + 4T + P) / 6

where,

TE = Pert Expected Time Duration,

O = Optimistic estimate, =2

T = Typical estimate,=3

P = Pessimistic estimate=8

TE = (O + 4T + P) / 6

=(2+4*3+8)/6

3.6666=3.67

σ = (P – O)/6

=(8-2)/6

=1