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Sergeeva-Olga [200]

3 years ago

8

Steven just got a new summer job painting fences in his neighborhood. He will be paid $7.25 an hour. His first customer paid him

a total of $36.25.
Part A:
If h = the number of hours Steven worked, write an equation that would show how the customer knew how much to pay him.

Part B:
Using the equation you wrote in Part A, how many total hours did Steven work?

(Explain in detail please.)

1 answer:

mote1985 [20]3 years ago

5 0

Answer:

a). The equation; 7.25 h-36.25=0

b). total number of hours Steven work=5 hours

Step-by-step explanation:

Part A

The expression for the total money earned is as follows;

T=E×h

where;

T=total earnings

E=earnings per hour

h=number of hours worked

In our case;

T=$36.25

E=$7.25

h=h

replacing;

36.25=(7.25×h)

36.25=7.25 h

The equation would be; 7.25 h=36.25, or 7.25 h-36.25=0

Part B

7.25 h=36.25

h=36.25/7.25

h=5

total number of hours Steven work=5 hours

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(b) $\log_5(\dfrac{625}{25})=2$

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Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

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$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

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$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

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$\log(100^3)=\log(10^6)$

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nadya68 [22]

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An uniform probability is a case of probability in which each outcome is equally as likely.

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