Answer:
log9
Step-by-step explanation:
hello :
note : a>0 and b>0
1) log(ab) = loga+logb
2) loga^n = nloga.....n in N
log(9x^5) + 5 log (1/x) = log(9x^5) + log (1/x)^5 = log((9x^5) (1/x)^5)
= log(9x^5)/(x^5)) = log9 because : (1/x)^5 = 1/x^5
Answer:
For f(x) = 2x + 3 and g(x) = -x 2 + 1, find the composite function defined by (f o g)(x)
(f o g)(x) = f(g(x))
= 2 (g(x)) + 3
= 2( -x 2 + 1 ) + 3
= - 2 x 2 + 5 Given f(2) = 3, g(3) = 2, f(3) = 4 and g(2) = 5, evaluate (f o g)(3)
Step-by-step explanation:
41×16 is 656 because 1×6 is 6. 6×4 is 24. 1×1 is 1. 1×4 is 4. The numbers left are 246 ( 1×6 + 6×4 ), and 41 ( 1×1 + 1×4 ). All together, the answer is 656. Enjoy! :)
The answer to the question is b
(√200/√5)= √40= √4*10= 2√10
Answer:
<h3>4cm</h3>
Step-by-step explanation:
