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bezimeni [28]
2 years ago
7

Solve for x.

Mathematics
1 answer:
exis [7]2 years ago
8 0

Answer:

11.2

Step-by-step explanation:

tan( <em>angle </em>) = <em>opposite / adjacent</em>

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10 runners ran fewer than 4 km 
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3 years ago
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Simplify.
marin [14]

1/2+(3/8−1/8)^2

= 1/2+(2/8)^2

= 1/2+(1/4)^2

= 1/2 + 1/16

= 8/16 + 1/16

= 9/16

Answer

9/16

3 0
3 years ago
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1. Kalena was asked to prove ifx(x - 1)(x + 1) = x3 - X represents a polynomial identity. She
Verdich [7]

Answer:

C. Kalena made a mistake in Step 3. The justification should state: -x²

+ x²

Step-by-step explanation:

Given the function x(x - 1)(x + 1) = x3 - X

To justify kelena proof

We will need to show if the two equations are equal.

Starting from the RHS with function x³-x

First we will factor out the common factor which is 'x' to have;

x(x²-1)

Factorising x²-1 using the difference of two square will give;

x(x+1)(x-1)

Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;

a²-b² = (a+b)(a-b) hence;

Factorising x²-1 using the difference of two square will give;

x(x+1)(x-1)

Factorising x(x+1) gives x²+x, therefore

x(x+1)(x-1) = (x²+x)(x-1)

(x²+x)(x-1) = x³-x²+x²-x

The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²

6 0
3 years ago
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>
4 0
3 years ago
Please anyone help me
Ksju [112]

Answer:

-52

Step-by-step explanation:

plug 2 into u(x) which is equal to

2(5) + 1= 5

plug 5 into w(x) which is equal to

-2(5^2) - 2

-2(25) - 2

-50 - 2 = -52

3 0
3 years ago
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