Given:
Quadrilaterals are given.
a)
Opposite sides are equal.
Length of the diagonals are equal.
Angles on four edges is 90 degree.
b)
All sides are equal.
c)
Length of the diagonals are not equal.
Opposite sides are equal.
d)
All sides are equal.
90 degree form in the intersection of the diagonal.
Answer:
Figure?
Step-by-step explanation:
Answer:
Mark has 13 marbles
Don has 40 marbles
Step-by-step explanation:
Let the number of Mark's Marbles = M
Let the number of Don's Marble = D
D = 1 + 3M - - - - (1) (Don has 1 more than 3 times the number of marbles Mark has)
D + M = 53 - - - - - (2) (total number of marbles is 53)
puttin the value of D from equation (1) into equation (2)
(1 + 3M) + M = 53
1 + 3M + M = 53
1 + 4M = 53
4M = 53 - 1 = 52
4M = 52
M = 52 ÷ 4
M = 13
finding D by putting the value of M (M = 13) into equation 1
D = 1 + 3M - - - - (1)
D = 1 + 3 (13)
D = 1 + 39
D = 40
∴ Mark has 13 marbles
Don has 40 marbles
Answer:
7 for all of them but the last one is 29
Step-by-step explanation:
i did it
The answers will be:
- (4, 5)
- remain constant and increase
- g(x) exceeds the value of f(x)
<h3>What is Slope and curve?</h3>
a) The slope of the curve g(x) roughly matches that of f(x) at about x=4. Above that point, the curve g(x) is steeper than f(x), so its average rate of change will exceed that of f(x). An appropriate choice of interval is (4, 5).
b) As x increases, the slope of f(x) remains constant (equal to 4). The slope of g(x) keeps increasing as x increases. An appropriate choice of rate of change descriptors is (remain constant and increase).
c) The curves are not shown in the problem statement for x = 8. The graph below shows that g(x) has already exceeded f(x) by x=7. It remains higher than f(x) for all values of x more than that. We can also evaluate the functions to see which is greater:
f(8) = 4·8 +3 = 35
g(8) = (5/3)^8 ≈ 59.54 . . . . this is greater than 35
g(8) > f(8)
d) Realizing that an exponential function with a base greater than 1 will have increasing slope throughout its domain, it seems reasonable to speculate that it will always eventually exceed any linear function (or any polynomial function, for that matter).
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