Given:
(2, 4) and (3, 3) are on the line.
To find:
The equation of line in point slope form.
Solution:
If a line passes through a point
with slope m, then the point slope form of the line is
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
(2, 4) and (3, 3) are on the line. So, slope of the line is
![m=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
![m=\dfrac{3-4}{3-2}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B3-4%7D%7B3-2%7D)
![m=\dfrac{-1}{1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B-1%7D%7B1%7D)
![m=-1](https://tex.z-dn.net/?f=m%3D-1)
The slope of a line is -1 and it passes through (2,4). So, an equation in point slope form is
![y-4=-1(x-2)](https://tex.z-dn.net/?f=y-4%3D-1%28x-2%29)
Therefore, an equation of the line in point slope form is
.
The answer is -202
Hope this helps! :)
Option 3 is the equivalent function.
1.04 to the 4th power is 1.1699
Hope this helps! Mark as Brainliest please! :)))