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3 years ago

Help me plz god bless

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

5 0

The answer is D for this questom

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John asked 60 people to name their favourite fruit here are his results

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Pears 15-30
Bananas 20-40

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3 years ago

Increase #500 in the ratio 16:10

Oxana [17]

Answer:

Answer is 900.

Step-by-step explanation:

To find:

Increase #500 in the ratio 16:10

Solution:

New Number: Old Number = 16:10

We are given the old number as 500.

Let the new number after increase = $x$

Now, using the above ratio:

 $x$ : 500 = 16:10

$\dfrac{x}{500} = \dfrac{16}{10}\\\Rightarrow x = 500 \times \dfrac{16}{10}\\\Rightarrow x = 50 \times 16\\\Rightarrow x = 900$

Therefore, the increased value of 500 in the ration 16:10 is 900.

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3 years ago

A rectangle has a length of 4 cm, a width

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19 is the answer to this question

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3 years ago

Using the information in the Box-and-Whisker plot below, what is the minimum value?

dexar [7]

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3 years ago

The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s

Molodets [167]

Answer:

500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

$f(x,y)=4x+2y\\g(x,y)=2x^2+y-4$

The Lagrangian is ...

$\mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2$

$\dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5$

Since x and y are in thousands, maximum profit is to be had when the company produces ...

500 Type A souvenirs, and 3500 Type B souvenirs

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3 years ago