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natita [175]
3 years ago
12

State the domain of f•g.

Mathematics
1 answer:
stepladder [879]3 years ago
5 0
<h3>Answer:  choice A</h3>

D: x > -3; \ (f \circ g)(x) = \frac{-7}{\sqrt{x+3}}

==================================

Explanation:

The idea is to start with f(x), then replace every copy of x with g(x) so that you end up with the composition function as shown below.

f(x) = \frac{-7}{x}\\\\f(g(x)) = \frac{-7}{g(x)}\\\\f(g(x)) = \frac{-7}{\sqrt{x+3}}\\\\(f \circ g)(x) = \frac{-7}{\sqrt{x+3}}\\\\

The notation f(g(x)) is the same as (f \circ g)(x)

I prefer f(g(x)) as it is more descriptive.

--------

Now onto computing the domain. We want to avoid dividing by zero, and we want to avoid taking the square root of a negative number.

This means the expression x+3 must be larger than 0. That way \sqrt{x+3} will also be larger than 0.

If x+3 > 0, then x > -3 after subtracting 3 from both sides.

As long as x is larger than -3, then it is a valid input to the composite function (f \circ g)(x)

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Define $g$ by $g(x)=5x-4$. If $g(x)=f^{-1}(x)-3$ and $f^{-1}(x)$ is the inverse of the function $f(x)=ax+b$, find $5a+5b$.
Slav-nsk [51]

Answer:

<h2>2</h2>

Step-by-step explanation:

Given g(x)=5x-4 and g(x)=f^{-1}(x)-3

Substituting g(x) =  5x-4 into the second equation we have;

5x-4 =  f^{-1}(x)-3

f^{-1}(x) = 5x-4+3

f^{-1}(x) = 5x-1

To get f(x), let us first make y to be equal  f^{-1}(x)

y = 5x-1

expressing x in terms of y to get f(x), we have;

5x = y+1

x = y/5+1/5

replacing y with x, we will have;

y = x/5 + 1/5

F(x) = x/5 + 1/5

Comparing x/5 + 1/5 with ax+b, a = 1/5 and b = 1/5

5a + 5b = 5(1/5)+ 5(1/5)

5a+5b = 1+1

5a+5b = 2

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