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nalin [4]
3 years ago
11

Which equation is modeled below?

Mathematics
1 answer:
malfutka [58]3 years ago
8 0

Answer:

number 1, answer x-4.

Step-by-step explanation:

Firstly, you group like terms like

2x-2x-2+6

=x-4

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What products result in a difference of squares?
lesya [120]

Answer:

cubes?

Step-by-step explanation:

4 0
3 years ago
Express the following in standard form.​
salantis [7]

<em>To write in standard form, we have to move the decimal point in  </em>

<em>3.42</em>

<em> over 3 places to the left since our exponent is  10 3 </em>

<em>This gives us our answer of  </em>

<em>0.00342</em>

<em>Hope this helps.</em>

6 0
3 years ago
Simplify the expression ~ 1.7 - 2.7 - 1.34 + 4.9 - 148 ~
Rainbow [258]

Answer:

-145.44

Step-by-step explanation:


6 0
4 years ago
Please help me with the below question.
tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.  

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

8 0
2 years ago
Tìm một đoạn nghiệm của phương trình<br> 3/x+1 +4/(x+1)^2+5/(x+1)^3+6/(x+1)^4=10
SVETLANKA909090 [29]

Answer:

btfrt34598fc

Step-by-step explanation:

6 0
3 years ago
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