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Elenna [48]
3 years ago
10

PLEASE HELP!

Mathematics
1 answer:
klio [65]3 years ago
5 0
  this is the best i got  and i like bobs burgers The actual probability of getting one of the three things he wants is 3/total number of sectios.
He thought it as since he needs to get 1 out of three items, so he did 1/3.
To get the correct answer, the number of items needed is divided with the total number of sections.
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An expression equivalent to -4(2k-6)
Aleksandr [31]

Answer:

-8k + 24

Step-by-step explanation:

Is your expression.

6 0
3 years ago
Solve for x.<br> 9(x - 2) = 18<br> o x=0<br> X = 16/9<br> x = 20/9
iragen [17]

Answer:

x = 4

Step-by-step explanation:

9(x - 2) = 18

9x - 18 = 18

9x = 18 + 18

9x = 36

x = 36/9

x = 4

5 0
3 years ago
Read 2 more answers
this year, 450 students are graduating from big lakes high school. of the graduates, 68% plan to got to collage next year, and 1
satela [25.4K]
54 students do not know what they're going to do after graduating
7 0
3 years ago
Anton works at the First National Bank. His employer offers him a pension retirement plan, which will be 1.45% of his average sa
shepuryov [24]

Answer:

31217.34

Step-by-step explanation:

92000+92800+99000+100500+105000=489300/5=97860 avg salary

97860X.0145=1418.97x22=31217.34

5 0
3 years ago
Solve the following equation with the initial conditions. x¨ + 4 ˙x + 53x = 15 , x(0) = 8, x˙ = −19
Katen [24]

x''+4x'+53x=15

has characteristic equation

r^2+4r+53=0

with roots at r=-2\pm7i. Then the characteristic solution is

x_c=C_1e^{(-2+7i)t}+C_2e^{(-2-7i)t}=e^{-2t}\left(C_1\cos(7t)+C_2\sin(7t)\right)

For the particular solution, consider the ansatz x_p=a_0, whose first and second derivatives vanish. Substitute x_p and its derivatives into the equation:

53a_0=15\implies a_0=\dfrac{15}{53}

Then the general solution to the equation is

x=e^{-2t}\left(C_1\cos(7t)+C_2\sin(7t)\right)+\dfrac{15}{53}

With x(0)=8, we have

8=C_1+\dfrac{15}{53}\implies C_1=\dfrac{409}{53}

and with x'(0)=-19,

-19=-2C_1+7C_2\implies C_2=-\dfrac{27}{53}

Then the particular solution to the equation is

\boxed{x(t)=\dfrac1{53}e^{-2t}(409cos(7t)-27\sin(7t)+15)}

8 0
3 years ago
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