400% of a is 4a
4a/400a = 1/100=1%
B is the most reasonable answer. -12 times 4 is -48 plus -3. That's a total of -51/4
Given:
Quadrilateral PQRS
P(o, o), Q(a+c, o), R(2a+c, b), S(a, b)
Find:
whether the diagonals are perpendicular using coordinate geometry
Solution:
If the diagonals are perpendicular, their slopes multiply to give -1.
The slope of PR is
(b-o)/(2a+c-o)
The slope of QS is
(b-o)/(a-(a+c)) = (b-o)/(-c)
The product of these slopes is
(b-o)·(b-o)/((2a+c-o)(-c))
This value will not be -1 except for very specific values of a, b, c, and o.
It cannot be concluded that the diagonals of PQRS are perpendicular based on the given coordinates.
Answer:
a) Radius: IK
b) Diameter: JF
c) Chord: GH
d) 4 (Because IK is a radius of 2 and that doubled is 4)
Step-by-step explanation: